Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

NicholasWong752

  • 3 years ago

Evaluate. ArcTan( sqrt3/ 3)

  • This Question is Closed
  1. NicholasWong752
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\tan^{-1} \frac{ \sqrt{3} }{ 3 }\]

  2. geerky42
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Let \(\theta\) be \( \tan^{-1} \dfrac{\sqrt{3}}{3} \). \(\tan \theta = \dfrac{\sqrt{3}}{3}\) At what angle is \(\tan \theta\) equal to \( \dfrac{\sqrt3}{3} \)?

  3. NicholasWong752
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    It's 30. But I don't know how I got that.

  4. NicholasWong752
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1357522052726:dw|

  5. geerky42
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Well, \(\tan 30^{\text{o}} = \dfrac{\sqrt3}{3}\) so it's true that \(30^{\text{o}} = \tan^{-1}\dfrac{\sqrt3}{3}\).|dw:1357522138906:dw|

  6. NicholasWong752
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I thought Tangent was opposite over adjacent.

  7. NicholasWong752
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    OH THEY RATIONALIZED IT

  8. geerky42
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    It is. Welcome.

  9. NicholasWong752
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    God damn it, tricky bastards. >:| Thanks a lot. xD

  10. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy