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NicholasWong752
 3 years ago
Evaluate. ArcTan( sqrt3/ 3)
NicholasWong752
 3 years ago
Evaluate. ArcTan( sqrt3/ 3)

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NicholasWong752
 3 years ago
Best ResponseYou've already chosen the best response.0\[\tan^{1} \frac{ \sqrt{3} }{ 3 }\]

geerky42
 3 years ago
Best ResponseYou've already chosen the best response.1Let \(\theta\) be \( \tan^{1} \dfrac{\sqrt{3}}{3} \). \(\tan \theta = \dfrac{\sqrt{3}}{3}\) At what angle is \(\tan \theta\) equal to \( \dfrac{\sqrt3}{3} \)?

NicholasWong752
 3 years ago
Best ResponseYou've already chosen the best response.0It's 30. But I don't know how I got that.

NicholasWong752
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1357522052726:dw

geerky42
 3 years ago
Best ResponseYou've already chosen the best response.1Well, \(\tan 30^{\text{o}} = \dfrac{\sqrt3}{3}\) so it's true that \(30^{\text{o}} = \tan^{1}\dfrac{\sqrt3}{3}\).dw:1357522138906:dw

NicholasWong752
 3 years ago
Best ResponseYou've already chosen the best response.0I thought Tangent was opposite over adjacent.

NicholasWong752
 3 years ago
Best ResponseYou've already chosen the best response.0OH THEY RATIONALIZED IT

NicholasWong752
 3 years ago
Best ResponseYou've already chosen the best response.0God damn it, tricky bastards. >: Thanks a lot. xD
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