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NicholasWong752Best ResponseYou've already chosen the best response.0
\[\tan^{1} \frac{ \sqrt{3} }{ 3 }\]
 one year ago

geerky42Best ResponseYou've already chosen the best response.1
Let \(\theta\) be \( \tan^{1} \dfrac{\sqrt{3}}{3} \). \(\tan \theta = \dfrac{\sqrt{3}}{3}\) At what angle is \(\tan \theta\) equal to \( \dfrac{\sqrt3}{3} \)?
 one year ago

NicholasWong752Best ResponseYou've already chosen the best response.0
It's 30. But I don't know how I got that.
 one year ago

NicholasWong752Best ResponseYou've already chosen the best response.0
dw:1357522052726:dw
 one year ago

geerky42Best ResponseYou've already chosen the best response.1
Well, \(\tan 30^{\text{o}} = \dfrac{\sqrt3}{3}\) so it's true that \(30^{\text{o}} = \tan^{1}\dfrac{\sqrt3}{3}\).dw:1357522138906:dw
 one year ago

NicholasWong752Best ResponseYou've already chosen the best response.0
I thought Tangent was opposite over adjacent.
 one year ago

NicholasWong752Best ResponseYou've already chosen the best response.0
OH THEY RATIONALIZED IT
 one year ago

NicholasWong752Best ResponseYou've already chosen the best response.0
God damn it, tricky bastards. >: Thanks a lot. xD
 one year ago
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