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- anonymous

What is a simpler form of the radical expression?
I need someone to check my answer!

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Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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- anonymous

What is a simpler form of the radical expression?
I need someone to check my answer!

- schrodinger

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- anonymous

- anonymous

It either 7|x^3|y^4 or 7x^3|y^4| I'm pretty sure it's the first one right?

- anonymous

Work out what 4th root 2401 is and the rest is probably more straightforward.

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- anonymous

Well, remember that \(|y^4| = y^4\) since anything to an even power is going to be positive.

- anonymous

This isn't the case for \(|x^3|\) which is why the absolute value bars must stay.

- anonymous

@Trillography Given what I said, you can figure it out with certainty, right?

- anonymous

Dude, both of my answers that I think are right have A.V. bars ...

- anonymous

Was going to say 3 or 4 but now I've got it.

- anonymous

Cheers wio. ;D

- anonymous

-x * -x * -x does not equal -x * -x
Good luck. BTW are we answering your monday maths homework? You've asked a few questions.

- anonymous

No, your definitely not. I've already finished all my hw. I'm working on a p. exam. I've asked more than a few and about 80% of them didn't get answers.

- anonymous

Ok 'x' flips its sign, potentially, if it starts out negative. As does the 'y' term. However, the 'y' term is multiplied an even number of times - whereas the 'x' term is multiplied an odd number of times.

- anonymous

So:
-1*-1=1
-1*-1*-1=-1
-1*-1-*1-*1=1
So by using the bars i.e. the absolute value we get answer (c.) that is 1 from zero.
Be it +1 or -1

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