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what unit and lesson
u in CA?
U4 L18, its the practice, i really need help with the hole thing LOL
just sittn and waiting.....
This question is a little tedious, because it takes multiple steps, in order to solve. But even though it's long, it's actually pretty easy. I'll show you. ~~~~~~~~~~~ The first thing we need to do is know how to read an amino acid chart. Here's the amino acid chart: http://dtc.pima.edu/blc/181/Lessons/L12/12step3/12step3images/genetic_code.gif (And in case you're wondering, there is only one amino acid chart. They're all the same.) If you remember from Biology, TRANSCRIPTION is where we go from DNA to RNA. And TRANSLATION is where we go from RNA to AMINO ACIDS. In order to solve this problem, we need to go backward. So first, we need to go from AMINO ACIDS to RNA. ~~~~~~~~~~~ Again, here is the same amino acid chart: http://dtc.pima.edu/blc/181/Lessons/L12/12step3/12step3images/genetic_code.gif Take a look at the chart. We already have the amino acids that we need to look for: Proline (Pro) Phenylalanine (Phe) Tyrosine (Tyr) Now, we need to look at the chart, for CODONS. CODONS are groups of THREE LETTERS. ~~~~~~~~~~~~~ Let's look at our first amino acid: (Pro) What three letters can make (Pro)? Look at the chart, and find (Pro). You can see that (Pro) comes up FOUR TIMES. That means that there are FOUR DIFFERENT CODONS that can make (Pro). CODONS are made of THREE letters. Remember this. So, look at where (Pro) appears on the chart. First, take the letter on the LEFT side of the chart. Then take the letter on the TOP of the chart. And finally, take the letter on the RIGHT side of the chart. Because (Pro) appears FOUR TIMES, you have to do those steps FOUR TIMES, for each place where (Pro) appears. Those four codons are... (C C U) (C C C) (C C A) (C C G) Any one of those four RNA codons can make (Pro). Remember, we're not talking about DNA yet. We're talking about RNA. ~~~~~~~~~~~~~ Now, let's look at our next amino acid: (Phe) Look at the amino acid chart, and find (Phe). You can see that (Phe) shows up TWO times. That means that there are TWO codons that can make (Phe). Look at the places where (Phe) appears. Take the letter on the LEFT. Take the letter on the TOP. Take the letter on the RIGHT. You have to do those steps, TWO times, because (Phe) appears TWO times, in two different places. The codons that can make (Phe) are... (U U U) (U U C) ~~~~~~~~~~~~~~ Now, let's look at our last amino acid: (Tyr) Look at the amino acid chart. Find the places where (Tyr) shows up. (Tyr) shows up TWO times. So, there are TWO codons that can make (Tyr). And those two codons are.... (U A U) (U A C) ~~~~~~~~~~~~~~ Now, let's go over everything we've found: The codons that can make (Pro) are.... (C C U) (C C C) (C C A) (C C G) The codons that can make (Phe) are.... (U U U) (U U C) The codons that can make (Tyr) are.... (U A U) (U A C) ~~~~~~~~~~~~~ Now, in order to answer the original question that you posted, we have to take these RNA codons, and work backward, into DNA codons. Again, you remember that in TRANSCRIPTION, DNA goes to RNA. A goes to U T goes to A C goes to G G goes to C We already have the RNA codons. We need to find the DNA codons now. Let's look at our first RNA codon, that makes (Pro). That's (C C U). What DNA codon can make the RNA codon (C C U)? The answer is (G G A). Remember, again, that from DNA to RNA.... A goes to U T goes to A C goes to G G goes to C So, (G G A) goes to (C C U). You see? ~~~~~~~~~~~ So, (G G A) is one possible DNA codon that can make (Pro), in the end. There are FOUR possible DNA codons, that can make (Pro) in the end. We have to figure out all for DNA codons, using the RNA that we already have. ~~~~~~~~~~~ I'm gonna stop right here, and I'll ask you... 1. Do you have any questions so far? 2. Can you look at our next RNA codon for (Pro), and tell me what DNA codon it would go with?
lesson 18 or 19?
1. How many different phenotypes are possible in the offspring of two parents with genotypes AA and aa, where A is the dominant allele for a trait and a is the recessive allele for the same trait? (1 point) (1 pt) one (0 pts) two (0 pts) three (0 pts) four 0 /1 point 2. A woman buys red-flowering and blue-flowering plants of the same species and plants them in her garden. The plant undergoes both self-fertilization and cross-fertilization. The woman collects seeds and plants them the following spring. What can the woman expect to observe in the flowers of the new generation of plants if the gene for flower color is codominant? (1 point) (0 pts) plants with red flowers and plants with blue flowers (0 pts) plants with both red and blue flowers (1 pt) plants with red flowers, plants with blue flowers, and plants with purple flowers (0 pts) plants with purple flowers 0 /1 point 3. What is formed at the end of meiosis? (1 point) (0 pts) two genetically identical cells (1 pt) four genetically different cells (0 pts) four genetically identical cells (0 pts) two genetically different cells 1 /1 point 4. Which of the following is true concerning DNA replication? (1 point) (0 pts) The original DNA molecule remains intact, although it acts as a template for the formation of a copy that contains two new antiparallel strands. (0 pts) The leading strand is copied in the 5’ to 3’ direction and the lagging strand is copied in the 3’ to 5’ direction. (0 pts) Both strands are copied to form Okazaki fragments, which are later annealed by DNA ligase. (1 pt) The replication process proceeds on both strands in the same direction, which requires that RNA primers bind to the lagging strand. 1 /1 point 5. Which of the following will be directly affected in a bacterial cell that has a mutation in its gene for RNA polymerase? (1 point) (0 pts) DNA replication (1 pt) transcription (0 pts) translation (0 pts) gene regulation 0 /1 point 6. Which of the following DNA sequences will result in the amino acid sequence –pro-phe-tyr-? (1 point) (1 pt) GGGAAAATG (0 pts) CCCUUUUAC (0 pts) GGGUUUUAG (0 pts) CCCTTTTTC 0 /1 point 7. Which of the following frameshift mutations might be expected to have the least impact on an organism? (1 point) (0 pts) a deletion of two nucleotides near the beginning of a gene (1 pt) an insertion of three nucleotides in the middle of a gene (0 pts) a deletion of four nucleotides near the end of a gene (0 pts) an insertion of five nucleotides at a gene’s promoter site 1 /1 point 8. If a mutation occurs in the gene for the lac repressor and results in a repressor that does not bind lactose, which of the following will be observed? (1 point) (1 pt) The mutant will not be able to grow on lactose. (0 pts) The mutant will only be able to grow on lactose. (0 pts) The mutant will be able to grow on lactose and on other sugars. (0 pts) The mutant will be harmed by the presence of lactose. 1 /1 point 9. If a man with blood type A and a woman with blood type B produce an offspring, what might be the offspring’s blood type? Blood Types Blood Type Combination of Alleles A IAIAor IAi B IBIBor IBi AB IAIB O ii (1 point) (0 pts) AB or O (0 pts) A, B, or O (1 pt) A, B, AB, or O (0 pts) AB only 1 /1 point 10. Which of the following would require the use of recombinant DNA? (1 point) (0 pts) crossing two apple trees to create better apples (0 pts) breeding a donkey and a horse to make a mule (1 pt) engineering bacteria that produce human insulin (0 pts) creating a polyploid banana tree 1 /1 point
@InYourHead Thanks for actually explaining the question and it's answer rather than copy and pasting answers like a dimbo. You helped a lot!