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jesusisabiscuit
Group Title
The derivative of f(x)=(x^4/3)(x^5/5) attains its maximum value at what x value?
a. 1
b. 0
c. 1
d. 4/3
e. 5/3
 one year ago
 one year ago
jesusisabiscuit Group Title
The derivative of f(x)=(x^4/3)(x^5/5) attains its maximum value at what x value? a. 1 b. 0 c. 1 d. 4/3 e. 5/3
 one year ago
 one year ago

This Question is Closed

jesusisabiscuit Group TitleBest ResponseYou've already chosen the best response.0
can you explain it to me, please?
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
find f''(x)
 one year ago

jesusisabiscuit Group TitleBest ResponseYou've already chosen the best response.0
f''(x) = 4x^2  3x^3 what next?
 one year ago

Lilmoney Group TitleBest ResponseYou've already chosen the best response.0
Isn't that it
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.2
Ummm, looks like your \(f''(x)\) is a bit off.
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
The condition To attain Max is f''(x) > 0
 one year ago

Lilmoney Group TitleBest ResponseYou've already chosen the best response.0
That is true
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.2
They want the max of the derivative.
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.2
So you want to find the critical numbers \(f''(x)=0\) or undefined. Then you'd plug them back into \(f'(x)\) to see where the max is.
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
nope @wio they ask..For where the max is attained
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.2
"The derivative of f(x)=(x^4/3)(x^5/5) attains its maximum" "f'(x) attains its maximum"
 one year ago

jesusisabiscuit Group TitleBest ResponseYou've already chosen the best response.0
aha! f"(x) = 4x^2  4x^3. i got my critical numbers. x = 0 & x = 1?
 one year ago

KingGeorge Group TitleBest ResponseYou've already chosen the best response.1
That looks good. So your local maximum value is at either x=0 or x=1. Also, since your first derivative is a negative quartic (has a \(x^4\) term), you have a parabola type shape opening downwards, so the local maximum is the global maximum. Now you just need to determine which one is the maximum.
 one year ago

KingGeorge Group TitleBest ResponseYou've already chosen the best response.1
make sense so far?
 one year ago

jesusisabiscuit Group TitleBest ResponseYou've already chosen the best response.0
i think. i got f'(0) = 0 and f'(1) = 1/3. so the answer is... 1?
 one year ago

jesusisabiscuit Group TitleBest ResponseYou've already chosen the best response.0
All riiiiiiiiight. thank you. and wio. but s/he left.
 one year ago

KingGeorge Group TitleBest ResponseYou've already chosen the best response.1
You're welcome.
 one year ago
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