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itsjustme_lol

please help

  • one year ago
  • one year ago

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  1. itsjustme_lol
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    a.) y = - 2x - 2 b.)y = - 3x - 2 c.)y = - 2x - 4 d.)y = - 3x - 4

    • one year ago
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  2. binarymimic
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    looks like a slope of -3 and y intercept of -4

    • one year ago
  3. nitz
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    i am not able to see the points clearly............can u just repost it by zooming

    • one year ago
  4. itsjustme_lol
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    yes hang on.

    • one year ago
  5. binarymimic
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    • one year ago
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  6. itsjustme_lol
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    well come to think of it..i cant see the points either

    • one year ago
  7. itsjustme_lol
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    thanks @binarymimic, i cant even see the points on the original picture on my screen

    • one year ago
  8. whpalmer4
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    Look at the graph to find points where you can see the exact values. (-2,2) and (-1,-1) are two such points. Difference of 1 in the x values gives a difference of -3 in the y values, so the slope is -3 (y goes down as x goes up). The y intercept is just the value of y where the line crosses the y axis, and that is -4. the formula for the line in slope intercept form is y = mx + b where m is slope and b is y-intercept, so y = -3x -4, choice d).

    • one year ago
  9. nitz
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    ya...........for sure its d firstly the y -intercept is -4 and secondly the graph passes through (-2,2)

    • one year ago
  10. itsjustme_lol
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    can you confirm my answer on my next one?

    • one year ago
  11. itsjustme_lol
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    What is the slope of a line perpendicular to the line in this graph? i got -1/3

    • one year ago
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  12. binarymimic
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    i think you forgot to take the reciprocal of it

    • one year ago
  13. itsjustme_lol
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    ohh so it would just be 1/3 instead of -1/3?

    • one year ago
  14. whpalmer4
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    Slope of a perpendicular line will be -1/m. m in this graph is 1/3 (3 units to the right for x to make 1 unit up for y), so the correct answer would be -1/(1/3) or -3. you want the line to be going steeply down from left to right

    • one year ago
  15. whpalmer4
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    move 1 unit right in x, down 3 in y

    • one year ago
  16. binarymimic
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    the reciprocal of a # is what you get when you take 1 divided by the #

    • one year ago
  17. itsjustme_lol
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    ohhh so -3..i see. sorry! lol

    • one year ago
  18. binarymimic
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    yeah

    • one year ago
  19. whpalmer4
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    always good to mark off a pair of points with the new equation to make sure the line is what you expect!

    • one year ago
  20. whpalmer4
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    so easy to make arithmetic or sign errors...

    • one year ago
  21. itsjustme_lol
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    ok i have one more question about graphing..do you guys want me to post in as a new question or just post it here? aand thankyou so much! and yes, I tend to make sign errors a lot lol

    • one year ago
  22. itsjustme_lol
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    i think i have the answer to my question..just want to get a second thought on it

    • one year ago
  23. whpalmer4
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    fire away

    • one year ago
  24. itsjustme_lol
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    Given the point (-4, 2) and a slope of -1

    • one year ago
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  25. itsjustme_lol
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    thats the answer im thinking...

    • one year ago
  26. binarymimic
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    did you draw that?

    • one year ago
  27. itsjustme_lol
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    heres the other ones that i had to choose from

    • one year ago
  28. itsjustme_lol
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    noo. too bad i still cant see the points..idk why they would put it soo small

    • one year ago
  29. whpalmer4
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    If the slope is -1, then it should move one point down and one to the right, like in aaa.gif

    • one year ago
  30. binarymimic
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    look carefully at the choices. which one has (-4, 2) as a point, and a slope of -1

    • one year ago
  31. itsjustme_lol
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    is it safe to choose ccc.gif or no?

    • one year ago
  32. whpalmer4
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    They've all got (-4,2) as a point. only aaa.gif has a slope of -1

    • one year ago
  33. itsjustme_lol
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    @whpalmer4 that makes more sense

    • one year ago
  34. whpalmer4
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    ccc.gif has a slope of -3/2

    • one year ago
  35. itsjustme_lol
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    idk whati was thinking lol. sorry :P

    • one year ago
  36. whpalmer4
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    it's late, unless you're in Asia :-)

    • one year ago
  37. itsjustme_lol
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    haha. can you help me with one more? thats is all. ill open it in a new question thoughif you are willing to

    • one year ago
  38. whpalmer4
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    okay

    • one year ago
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