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\[\lim_{x \rightarrow 0}[\frac{ e ^{tanx}e^x }{ tanx  x }]\]
 one year ago
 one year ago
Yahoo! Group Title
\[\lim_{x \rightarrow 0}[\frac{ e ^{tanx}e^x }{ tanx  x }]\]
 one year ago
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RONNCC Group TitleBest ResponseYou've already chosen the best response.0
so just use l'hopitals
 one year ago

RONNCC Group TitleBest ResponseYou've already chosen the best response.0
try that and then i can fix if you have more problems
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
i tried LHospital..it is werid...
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.0
d(e^tanx e^x)/dx e^tanx (sec^2 x) e^x
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.0
d(tanx x)/dx sec^2 x 1
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
L'Hospital's, Chain Rule and Quotient Rule! I'd die doing this question O_O
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.0
But lim x>0 sec^2 x1 =0
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.0
Again use L'Hospital's Rule ???
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
sec^2 x1 = tan^2 x
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
try using expressing in this form ... sorry don't have much time http://www.wolframalpha.com/input/?i=lim+x%3E0+%28e^x1%29%2Fx
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
this is interesting dw:1357557494779:dw
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
@sauravshakya @experimentX
 one year ago

UsukiDoll Group TitleBest ResponseYou've already chosen the best response.0
oh my lord...quotient rule will send chills
 one year ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.0
using L'Hôpital's rule \[ \large \lim_{x\to0}\frac{e^{\tan x}e^x}{\tan xx}= \lim_{x\to0}\frac{e^{\tan x}\sec^2xe^x}{\sec^2x1} \] \[ \large =\lim_{x\to0}\frac{e^{\tan x}\sec^4x+e^{\tan x}2\sec^2x\tan xe^x}{2\sec^2x\tan x} \]
 one year ago

UsukiDoll Group TitleBest ResponseYou've already chosen the best response.0
I see some factoring... e^tanx sec^2x
 one year ago

ghazi Group TitleBest ResponseYou've already chosen the best response.0
L'H rule wont work here, use expansion
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
Did nt get u @ghazi
 one year ago

ghazi Group TitleBest ResponseYou've already chosen the best response.0
L' Hospital's rule wont be helpful here you will be getting 0/0 form use expansion of functions
 one year ago

UsukiDoll Group TitleBest ResponseYou've already chosen the best response.0
oh wikipedia the true online source for Britannica related stuff, share with me this...KNOWLEDGE! http://en.wikipedia.org/wiki/L%27H%C3%B4pital%27s_rule
 one year ago

sirm3d Group TitleBest ResponseYou've already chosen the best response.2
hmm, i got 1, but i used series.
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
Can u show it up ?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
dw:1357560889084:dw
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
multiply and divide by x tan x.
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
got that ^ ?
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
Yeah...!...@sirm3d i also ..like..u see ur Approach ..Plzz
 one year ago

sirm3d Group TitleBest ResponseYou've already chosen the best response.2
\[e^{\tan x}=1+\frac{\tan x}{1!} + \frac{\tan^2x}{2!}+\cdots\\e^{x}=1+\frac{x}{1!} + \frac{x^2}{2!}+\cdots\\e^{\tan x}e^x=\frac{\tan x  x}{1!}+\frac{\tan^x  x^2}{2!}+\cdots\]
 one year ago

sirm3d Group TitleBest ResponseYou've already chosen the best response.2
each numerator has a factor \(\displaystyle \tan x  x\) \[\Large \frac{e^{\tan x}e^x}{\tan x  x}=\frac{(\tan x  x)(\frac{1}{1!}+\frac{\tan x + x}{2!}+\frac{\tan^x+x \tan x+x^2}{3!}+\cdots)}{\tan x  x}\]
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
That helps...too.....@sirm3d thxxx
 one year ago
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