• anonymous
I'm a bit confused. I thought I'd solved the problem but when running the integral through Wolframalpha the answer is totally different, am I wrong or is it just the wolframalpha algorithm that doesn't process things like me? http://www.wolframalpha.com/input/?i=integrate+sin^3(x)cos(x) $\int\limits_{}^{}\sin ^{3}(x) \cos(x) dx$ $\int\limits_{}^{}(1-\cos ^{2}(x))\cos(x)\sin(x) dx$ $u= \cos(x); -du=\sin(x) dx$ $-\int\limits_{}^{}(1-u ^{2})u du= -\int\limits_{}^{}u-u ^{3} du=-\frac{ u ^{2} }{ 2 }+\frac{ u ^{4} }{ 4} +C$ $=-\frac{\cos ^{2}(x) }{ 2 }+\frac{\cos ^{4}(x) }{ 4}+C$
Mathematics
• Stacey Warren - Expert brainly.com
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SOLVED
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