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 2 years ago
6. A rocket is launched from atop a 68foot cliff with an initial velocity of 155 ft/s. The height of the rocket above the ground at time t is given by h = –16t2 + 155t + 68. When will the rocket hit the ground after it is launched? Round to the nearest tenth of a second.
 2 years ago
6. A rocket is launched from atop a 68foot cliff with an initial velocity of 155 ft/s. The height of the rocket above the ground at time t is given by h = –16t2 + 155t + 68. When will the rocket hit the ground after it is launched? Round to the nearest tenth of a second.

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Hero
 2 years ago
Best ResponseYou've already chosen the best response.1Hint: Since h represents the height of the rocket, set h = 0, then solve for t.

Hero
 2 years ago
Best ResponseYou've already chosen the best response.1So solve 0 = –16t^2 + 155t + 68

cubanafabien1996
 2 years ago
Best ResponseYou've already chosen the best response.0okay thank you

Hero
 2 years ago
Best ResponseYou've already chosen the best response.1Did you solve it yet? If so, post your steps and let me know what you got.

cubanafabien1996
 2 years ago
Best ResponseYou've already chosen the best response.0not yet.. i'm trying too but idk how too

Hero
 2 years ago
Best ResponseYou've already chosen the best response.1Where have you done so far?

Hero
 2 years ago
Best ResponseYou've already chosen the best response.1Basically, that means you don't know how to factor a quadratic equation.
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