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6. A rocket is launched from atop a 68foot cliff with an initial velocity of 155 ft/s. The height of the rocket above the ground at time t is given by h = –16t2 + 155t + 68. When will the rocket hit the ground after it is launched? Round to the nearest tenth of a second.
 one year ago
 one year ago
6. A rocket is launched from atop a 68foot cliff with an initial velocity of 155 ft/s. The height of the rocket above the ground at time t is given by h = –16t2 + 155t + 68. When will the rocket hit the ground after it is launched? Round to the nearest tenth of a second.
 one year ago
 one year ago

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HeroBest ResponseYou've already chosen the best response.1
Hint: Since h represents the height of the rocket, set h = 0, then solve for t.
 one year ago

HeroBest ResponseYou've already chosen the best response.1
So solve 0 = –16t^2 + 155t + 68
 one year ago

cubanafabien1996Best ResponseYou've already chosen the best response.0
okay thank you
 one year ago

HeroBest ResponseYou've already chosen the best response.1
Did you solve it yet? If so, post your steps and let me know what you got.
 one year ago

cubanafabien1996Best ResponseYou've already chosen the best response.0
not yet.. i'm trying too but idk how too
 one year ago

HeroBest ResponseYou've already chosen the best response.1
Where have you done so far?
 one year ago

HeroBest ResponseYou've already chosen the best response.1
Basically, that means you don't know how to factor a quadratic equation.
 one year ago
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