## AshhSmith 2 years ago Can somebody please help with the steps to doing this ?? Part 1: Make up an angle measure for angle C and a length for one of the sides (AB, BC, or CA). Part 2: Use a trigonometric ratio (sine, cosine, or tangent) to solve for one of the other side lengths.

1. AshhSmith

2. AshhSmith

Part 1: c = 45 and length for CA is 5??

3. mathstudent55

If m<C = 45, then m<A = 45, and m<B = 90. You have a 45-45-90 triangle. In a 45-45-90 traingle, the two legs are congruent (they have the same length). The hypotenuse is sqrt(2) times longer than the 2 legs.

4. tcarroll010

Since C is 45, then so is A. So, this will be an isosceles triangle and the measure of AB will equal the measure of BC. The sine of C = AB/AC. sine 45 = AB/AC (AC) sine 45 = AB = BC

5. tcarroll010

btw the sine 45 = [sqrt(2)] / 2

6. AshhSmith

Its supposed to be a right triangle.. i just added the angle measures on my own

7. tcarroll010

Yes. All the above that I wrote bore that in mind.

8. tcarroll010

So, AB = (5)(sqrt 2) / 2

9. AshhSmith

10. tcarroll010

For the length of AB, that's the answer. If you multiplied it out, you would get AB = 3.53553 etc.

11. tcarroll010

Is this making sense to you now?

12. AshhSmith

yes alot more than before !

13. tcarroll010

It's good that this is going well for you. Remember, sine = opposite over hypotenuse.

14. tcarroll010

Good luck to you in all of your studies and thx for the recognition! @AshhSmith

15. AshhSmith

ty !

16. tcarroll010

uw!