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AshhSmith
Can somebody please help with the steps to doing this ?? Part 1: Make up an angle measure for angle C and a length for one of the sides (AB, BC, or CA). Part 2: Use a trigonometric ratio (sine, cosine, or tangent) to solve for one of the other side lengths.
Part 1: c = 45 and length for CA is 5??
If m<C = 45, then m<A = 45, and m<B = 90. You have a 45-45-90 triangle. In a 45-45-90 traingle, the two legs are congruent (they have the same length). The hypotenuse is sqrt(2) times longer than the 2 legs.
Since C is 45, then so is A. So, this will be an isosceles triangle and the measure of AB will equal the measure of BC. The sine of C = AB/AC. sine 45 = AB/AC (AC) sine 45 = AB = BC
btw the sine 45 = [sqrt(2)] / 2
Its supposed to be a right triangle.. i just added the angle measures on my own
Yes. All the above that I wrote bore that in mind.
So, AB = (5)(sqrt 2) / 2
For the length of AB, that's the answer. If you multiplied it out, you would get AB = 3.53553 etc.
Is this making sense to you now?
yes alot more than before !
It's good that this is going well for you. Remember, sine = opposite over hypotenuse.
Good luck to you in all of your studies and thx for the recognition! @AshhSmith