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AGummiBear55 Group Title

HELP!! n an 1 4 2 12 3 28 4 60 Which recursive equation represents the pattern? an = an – 1 + 2n an = an – 1 + 2(n + 1) an = an – 1 + 2n + 1 an = an – 1 + 2n + 1

  • one year ago
  • one year ago

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  1. Helper93 Group Title
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    All you need to do is to plug in both a and an and see which one is equal.

    • one year ago
  2. AGummiBear55 Group Title
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    yeah, but what is the equation?

    • one year ago
  3. mathstudent55 Group Title
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    12 - 4 = 8 28 - 12 = 16 60 - 28 = 32 Why are the third and fourth choices equal?

    • one year ago
  4. Helper93 Group Title
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    You find which one is the right one by trying every equation till you get both sides equal.

    • one year ago
  5. mathstudent55 Group Title
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    Are some n's and (n-1)'s subscripts and exponents?

    • one year ago
  6. AGummiBear55 Group Title
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    I'm still a lot confused on what the heck to do...

    • one year ago
  7. AGummiBear55 Group Title
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    @mathstudent55 What do I subtract 60 by?

    • one year ago
  8. AGummiBear55 Group Title
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    Grr.. Im so confused!! :/

    • one year ago
  9. mathstudent55 Group Title
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    n an 1 4 2 12 4 + 8 4 + 2^3 3 28 12 + 16 12 + 2^4 4 60 28 + 32 28 + 2^5 Do you see a pattern? Each term, an, is obtained by adding the previous term to 2 to the power n + 1

    • one year ago
  10. mathstudent55 Group Title
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    The way you wrote the choices makes no sense. There must be some exponents and subscripts there. You wrote everything as if it were simple numbers.

    • one year ago
  11. mathstudent55 Group Title
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    |dw:1357592071491:dw|

    • one year ago
  12. mathstudent55 Group Title
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    None of the choices you gave represent the recursive rule. Also, the third and fourth choices in your post are the same.

    • one year ago
  13. AGummiBear55 Group Title
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    • one year ago
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  14. AGummiBear55 Group Title
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    oops, sorry about that. :/

    • one year ago
  15. mathstudent55 Group Title
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    Look at last choice. It's what I wrote. Look again at the pattern I wrote, and see how I arrived at choice #4

    • one year ago
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