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anonymous
 4 years ago
Determine whether the graph of y = x^2 + 2x − 8 has a maximum or minimum point, then find the maximum or minimum value
anonymous
 4 years ago
Determine whether the graph of y = x^2 + 2x − 8 has a maximum or minimum point, then find the maximum or minimum value

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@zaynahf can you please help me?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Just a minute, im getting my notes

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ok do you know which way the parabola is going? Up or down?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i think up because the x^2 is positive

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Right! So based on that, it tells you whether your vertex will have a maximum or minimum value. When it is opening up (a value is +), there will be a minimum because the vertex is on the bottom, the lowest point of the parabola. When it is opening down (a value is ), there will be a maximum value because the vertex is at the top, the highest point of the parabola. When naming the min/max, you only use the y value of the vertex. Example:dw:1357599979562:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0One more thing: IF you know how to find a vertex when it is in standard form, you can do that, but personally i find it easier to first complete the square (make it into vertex form). If you need to know how to do either, let me know.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how do i put it in vertex form?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'll give you an example one, if you dont mind

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1357600335929:dwdw:1357600792411:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh that make sense they dont teach that in virtual school

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I have a link if you want it

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0http://www.youtube.com/watch?v=aDHq_FoRxZQ Explains it better than i did

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0would the vertex be (0.33,10.33)?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0How did you get that?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0tried the formula by plugging in the numbers

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0wait this ask for the minimum value not the vertex

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So if thats the vertex, then what would be the minimum?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0im lost i may have made terrible mistakes

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ok, where are you lost from?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0everything my brain just committed suicied i made mistakes a the beging all the way to the end

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0for finding the vertex?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i... thats what i tried but i messed up completely i didnt even simplify right

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0where did youget up to?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i failed at even isolating the x terms( i've been up since 3 am) :(

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Isolate: (x^2 +2x )8

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ill be on later i have to go eat dinner
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