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@zaynahf can you please help me?
Just a minute, im getting my notes
Ok do you know which way the parabola is going? Up or down?
i think up because the x^2 is positive
yeah it opens up
Right! So based on that, it tells you whether your vertex will have a maximum or minimum value. When it is opening up (a value is +), there will be a minimum because the vertex is on the bottom, the lowest point of the parabola. When it is opening down (a value is -), there will be a maximum value because the vertex is at the top, the highest point of the parabola. When naming the min/max, you only use the y value of the vertex. Example:|dw:1357599979562:dw|
One more thing: IF you know how to find a vertex when it is in standard form, you can do that, but personally i find it easier to first complete the square (make it into vertex form). If you need to know how to do either, let me know.
how do i put it in vertex form?
I'll give you an example one, if you dont mind
oh that make sense they dont teach that in virtual school
I have a link if you want it
http://www.youtube.com/watch?v=aDHq_FoRxZQ Explains it better than i did
would the vertex be (-0.33,-10.33)?
How did you get that?
-1,-9 if i round?
tried the formula by plugging in the numbers
Yep, its -1,-9
wait this ask for the minimum value not the vertex
So if thats the vertex, then what would be the minimum?
im lost i may have made terrible mistakes
Ok, where are you lost from?
everything my brain just committed suicied i made mistakes a the beging all the way to the end
for finding the vertex?
i... thats what i tried but i messed up completely i didnt even simplify right
where did youget up to?
i failed at even isolating the x terms( i've been up since 3 am) :-(
Isolate: (x^2 +2x )-8
ill be on later i have to go eat dinner