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mathmate
 2 years ago
Best ResponseYou've already chosen the best response.1You will get help as soon as you post your problem or topic. :)

kellyp73
 2 years ago
Best ResponseYou've already chosen the best response.0lol ok dw:1357604018475:dw

mathmate
 2 years ago
Best ResponseYou've already chosen the best response.1Is it: \(\huge (\frac{2q^4}{7})^4 \) ?

kellyp73
 2 years ago
Best ResponseYou've already chosen the best response.0yes how did you get that on there ?

mathmate
 2 years ago
Best ResponseYou've already chosen the best response.1You type *( \huge(\frac{2q^4}{7})^4 *) except you replace the two * at the beginning and the end by \. Anyway, everything inside has to be raised to the fourth power, so it becomes: \( \huge(\frac{2^4(q^4)^4}{7^4}) \) = \( \huge(\frac{16q^{16}}{2401}) \)

kellyp73
 2 years ago
Best ResponseYou've already chosen the best response.0i am really confused on all the 4 and the q

mathmate
 2 years ago
Best ResponseYou've already chosen the best response.1Using the rules of exponents which says that \(\huge (\frac{a}{b})^c \) = \(\huge \frac{a^c}{b^c} \) And you can take it from here. (sorry, got to go)

kellyp73
 2 years ago
Best ResponseYou've already chosen the best response.0thank you for you help
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