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Dido525
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The base of the solid is in the region between the xaxis and the parabola y=4x^2. The cross sections of the solid Perpendicular to the yaxis are semicircles. Compute the volume of the solid.
 one year ago
 one year ago
Dido525 Group Title
The base of the solid is in the region between the xaxis and the parabola y=4x^2. The cross sections of the solid Perpendicular to the yaxis are semicircles. Compute the volume of the solid.
 one year ago
 one year ago

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Dido525 Group TitleBest ResponseYou've already chosen the best response.0
I realize I am Integrating with respect to y since the semicircles are perpendicular to the yaxis. I found the intersection points to be from 2 to 2. Those are also the limits of integration. I am having trouble setting up the integral however.
 one year ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
I also know that the area of a semicircle is:\[\frac{ \pi r^2 }{ 2 }\]
 one year ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
@campbell_st @Hero @AravindG @Agent_Sniffles
 one year ago

precal Group TitleBest ResponseYou've already chosen the best response.0
I think if you draw it, it helps but this is not my strong point
 one year ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
Ohh I forgot to mention since I am integrating with respect to y the limits of integration are from 0 to 4 sorry.
 one year ago

precal Group TitleBest ResponseYou've already chosen the best response.0
still not my strong point
 one year ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
Thanks anyways :) .
 one year ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
dw:1357612463086:dw
 one year ago

precal Group TitleBest ResponseYou've already chosen the best response.0
sorry I wish I could help @satellite73 can you help on this one?
 one year ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
Don't worry about it. :) . I almost have it but I wonder if I can change the "r" in the semicircle to an x in someway/
 one year ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
Never mind. I got it.
 one year ago
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