anonymous
  • anonymous
Quadratics word problem
Mathematics
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
katieb
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
An arrow is shot upward from a platform 40 feet high with an initial velocity of 224 ft. per second. its height, h, in feet after t seconds is given by the equation: h= -16t^2 + 224t+40. At what times will the arrow be 824 feet above the ground?
anonymous
  • anonymous
Am i supposed to plug in 824 for t?
anonymous
  • anonymous
no, \(t\) is the time you are looking for you are supposed to replace \(h\) by 824 and solve for \(t\)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
h is replaced by 824
anonymous
  • anonymous
\[ \begin{array}{rcl} h(t) &=& -16t^2 + 224t+40 \\ 824 &=& -16t^2 + 224t+40 \\ 0 &=& -16t^2 + 224t+40-824 \end{array} \] Quadratic formula.
anonymous
  • anonymous
Ohh ok i see it now.. then you just factor, correct?
anonymous
  • anonymous
Ummm, you're solving for \(t\) here. You can factor or use quadratic formula or whatever method you want.
anonymous
  • anonymous
I see.. thanks!

Looking for something else?

Not the answer you are looking for? Search for more explanations.