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zaynahf
 2 years ago
Best ResponseYou've already chosen the best response.0An arrow is shot upward from a platform 40 feet high with an initial velocity of 224 ft. per second. its height, h, in feet after t seconds is given by the equation: h= 16t^2 + 224t+40. At what times will the arrow be 824 feet above the ground?

zaynahf
 2 years ago
Best ResponseYou've already chosen the best response.0Am i supposed to plug in 824 for t?

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0no, \(t\) is the time you are looking for you are supposed to replace \(h\) by 824 and solve for \(t\)

wio
 2 years ago
Best ResponseYou've already chosen the best response.2\[ \begin{array}{rcl} h(t) &=& 16t^2 + 224t+40 \\ 824 &=& 16t^2 + 224t+40 \\ 0 &=& 16t^2 + 224t+40824 \end{array} \] Quadratic formula.

zaynahf
 2 years ago
Best ResponseYou've already chosen the best response.0Ohh ok i see it now.. then you just factor, correct?

wio
 2 years ago
Best ResponseYou've already chosen the best response.2Ummm, you're solving for \(t\) here. You can factor or use quadratic formula or whatever method you want.
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