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zaynahf
 one year ago
Best ResponseYou've already chosen the best response.0An arrow is shot upward from a platform 40 feet high with an initial velocity of 224 ft. per second. its height, h, in feet after t seconds is given by the equation: h= 16t^2 + 224t+40. At what times will the arrow be 824 feet above the ground?

zaynahf
 one year ago
Best ResponseYou've already chosen the best response.0Am i supposed to plug in 824 for t?

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0no, \(t\) is the time you are looking for you are supposed to replace \(h\) by 824 and solve for \(t\)

wio
 one year ago
Best ResponseYou've already chosen the best response.2\[ \begin{array}{rcl} h(t) &=& 16t^2 + 224t+40 \\ 824 &=& 16t^2 + 224t+40 \\ 0 &=& 16t^2 + 224t+40824 \end{array} \] Quadratic formula.

zaynahf
 one year ago
Best ResponseYou've already chosen the best response.0Ohh ok i see it now.. then you just factor, correct?

wio
 one year ago
Best ResponseYou've already chosen the best response.2Ummm, you're solving for \(t\) here. You can factor or use quadratic formula or whatever method you want.
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