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zaynahf Group TitleBest ResponseYou've already chosen the best response.0
An arrow is shot upward from a platform 40 feet high with an initial velocity of 224 ft. per second. its height, h, in feet after t seconds is given by the equation: h= 16t^2 + 224t+40. At what times will the arrow be 824 feet above the ground?
 one year ago

zaynahf Group TitleBest ResponseYou've already chosen the best response.0
Am i supposed to plug in 824 for t?
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
no, \(t\) is the time you are looking for you are supposed to replace \(h\) by 824 and solve for \(t\)
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.0
h is replaced by 824
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.2
\[ \begin{array}{rcl} h(t) &=& 16t^2 + 224t+40 \\ 824 &=& 16t^2 + 224t+40 \\ 0 &=& 16t^2 + 224t+40824 \end{array} \] Quadratic formula.
 one year ago

zaynahf Group TitleBest ResponseYou've already chosen the best response.0
Ohh ok i see it now.. then you just factor, correct?
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.2
Ummm, you're solving for \(t\) here. You can factor or use quadratic formula or whatever method you want.
 one year ago

zaynahf Group TitleBest ResponseYou've already chosen the best response.0
I see.. thanks!
 one year ago
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