Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Determine the number and type of solutions

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SIGN UP FOR FREE
Determine the number and type of solutions for x2 + 4x + 3=0
x^2+4x+3=0
Quadratic equations has two solutions

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Unless it is perfect square
2 Rational?
Since , b^2 -4ac >0 two rational solution
Compare your Quadratic equation with ax^2+bx+c=0 find a,b,c. calculate b^2-4ac if b^2-4ac is positive -----> 2 real roots. if b^2-4ac is 0---->1 repeated real root. if b^2-4ac is negative ---->2 imaginary roots..
what about this one? What is the range of the graph of y = (x – 4)^2 + 3?
@sauravshakya b^2-4ac>0 doesnt mean roots are rational.
if b^2-4ac is perfect square -----> 2 rational roots.
I mean real solutions
ok so its what i though, 2 rational can someone help me on my other question

Not the answer you are looking for?

Search for more explanations.

Ask your own question