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boomerang285
Group Title
Can someone check my answers before I turn them in?
1. Write equation in its logarithmic form: 8^y=300.
MY ANSWER: log(base)8*300=y
2. use properties of logarithms to expand the logarithmic expression as much as possible: log(b) x^7.
MY ANSWER: 7*log(b)x
3. use properties of logarithms to condense each logarithmic expression. Write the expression as a single logarithm whose coefficient is 1: 5 log(b) x + 6 log(b) y
MY ANSWER: log(b) x^5 y^6
4. use common logarithms or natural logarithms and a calculator to evaluate to four decimal places: log(16) 57.2
MY ANSWER: 1.4595
 one year ago
 one year ago
boomerang285 Group Title
Can someone check my answers before I turn them in? 1. Write equation in its logarithmic form: 8^y=300. MY ANSWER: log(base)8*300=y 2. use properties of logarithms to expand the logarithmic expression as much as possible: log(b) x^7. MY ANSWER: 7*log(b)x 3. use properties of logarithms to condense each logarithmic expression. Write the expression as a single logarithm whose coefficient is 1: 5 log(b) x + 6 log(b) y MY ANSWER: log(b) x^5 y^6 4. use common logarithms or natural logarithms and a calculator to evaluate to four decimal places: log(16) 57.2 MY ANSWER: 1.4595
 one year ago
 one year ago

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shubhamsrg Group TitleBest ResponseYou've already chosen the best response.0
first 3 seem alright,,4th doesnt..
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.0
that'd require you to change bases first..what was your attempt ?
 one year ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.1
hmm, I took the log of 57.2 and divided it by the log of 16.
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.0
yes the method is correct! please recheck your calculations in that case..
 one year ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.1
1.2041?
 one year ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.1
ok awesome :)
 one year ago
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