The perimeter of the triangle with sides 5cm , 6cm and x cm is less than 18cm. Given that the sum of any two of the sides is always greater than the third side, find the range of values of x.

- anonymous

- katieb

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- anonymous

5 + 6 + x < 18
11 + x < 18
x<7
im not quite sure though :)

- anonymous

That's what i did and it's WRONG.

- anonymous

hmmm why?

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## More answers

- anonymous

answer is 1

- anonymous

how'd you get it? i dont seem to understand something about it

- anonymous

Because you and i made the same mistake, we only read the first part of the question and "ignore" the second sentence.

- anonymous

5+6+x<18
11+x<18
x<7

- anonymous

so it must be 1

- anonymous

@Sgstudent keep rocking

- anonymous

yea it must be 1

- anonymous

how did we get that?

- anonymous

so 5 +6 > x ??

- anonymous

i showed ya up there

- anonymous

why is it 1

- anonymous

sum of three sides is less than 18
5+6+x<18
subtract 11 on both sides
x<7
now it cant be 0 or a negative integer

- anonymous

waah i dont get it T.T where'd you get the 1?

- anonymous

same here

- anonymous

where would you get the 1 sir?

- anonymous

well look if it will be less than 1 then sum of two sides wont be greater than the third side ;)

- anonymous

that's like trail and error.

- anonymous

nvm if you cant explain how did you got the 1.

- anonymous

I get it already :)

- anonymous

i think i understood it already see if the othe side is 1 then 5 + 1 would be equal to 6 right? since we need the third to be greater and not equal to the sum then we use 2 and 2 is greater than 1 so if we would put it in a situation where x = 2 then we'll get
5 + 6 + 2 < 18
13 < 18
5+6 > 2
11 >2
5+2 > 6
7>6
6 + 2 > 5
8 > 5

- anonymous

great :)

- anonymous

We must fulfill the second sentence criteria to find the range of values of x hence, the range would be 1

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