The perimeter of the triangle with sides 5cm , 6cm and x cm is less than 18cm. Given that the sum of any two of the sides is always greater than the third side, find the range of values of x.

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The perimeter of the triangle with sides 5cm , 6cm and x cm is less than 18cm. Given that the sum of any two of the sides is always greater than the third side, find the range of values of x.

Mathematics
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5 + 6 + x < 18 11 + x < 18 x<7 im not quite sure though :)
That's what i did and it's WRONG.
hmmm why?

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answer is 1
how'd you get it? i dont seem to understand something about it
Because you and i made the same mistake, we only read the first part of the question and "ignore" the second sentence.
5+6+x<18 11+x<18 x<7
so it must be 1
@Sgstudent keep rocking
yea it must be 1
how did we get that?
so 5 +6 > x ??
i showed ya up there
why is it 1
sum of three sides is less than 18 5+6+x<18 subtract 11 on both sides x<7 now it cant be 0 or a negative integer
waah i dont get it T.T where'd you get the 1?
same here
where would you get the 1 sir?
well look if it will be less than 1 then sum of two sides wont be greater than the third side ;)
that's like trail and error.
nvm if you cant explain how did you got the 1.
I get it already :)
i think i understood it already see if the othe side is 1 then 5 + 1 would be equal to 6 right? since we need the third to be greater and not equal to the sum then we use 2 and 2 is greater than 1 so if we would put it in a situation where x = 2 then we'll get 5 + 6 + 2 < 18 13 < 18 5+6 > 2 11 >2 5+2 > 6 7>6 6 + 2 > 5 8 > 5
great :)
We must fulfill the second sentence criteria to find the range of values of x hence, the range would be 1

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