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boomerang285

  • one year ago

Please check this logarithm question... The loudness level of sound can be expressed by comparing the sound's intensity to the intensity of a sound barely audible tot he human ear. The formula D = 10(log I - log I0) describes the loudness level of a sound. D, in decibels, where I is the intensity of the sound, in watts per meter^2, and I(0) is the intensity of a sound barely audible to the human ear. a. Express the formula so that the expression in parentheses is written as a single logarithm. b. Continued below...

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  1. boomerang285
    • one year ago
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    b. Use the form of the formula from part (a) to answer this question: If a sound has an intensity 100 times the intensity of a softer sound how much larger on the decibel scale is the loudness level of the more intense sound.

  2. boomerang285
    • one year ago
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    My Answers. A. \[D=10*(Log(\frac{ I }{ I _{0} }))\] B. D=20

  3. Sgstudent
    • one year ago
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    Logarithm is a confusing topic. I am also equally confuse about the concepts.

  4. boomerang285
    • one year ago
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    Yes I know,, I just want to make sure I have these right before I turn them in...

  5. sauravshakya
    • one year ago
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    |dw:1357649064572:dw|

  6. sauravshakya
    • one year ago
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    Looks correct

  7. boomerang285
    • one year ago
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    this is what i have D = 10log(100Io/Io) D = 10log(100) D = 10*2 D = 20

  8. boomerang285
    • one year ago
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    so 20 is correct?

  9. sauravshakya
    • one year ago
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    yes

  10. boomerang285
    • one year ago
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    thank you so much for checking! :-)

  11. sauravshakya
    • one year ago
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    welcome

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