## anonymous 3 years ago Please check this logarithm question... The loudness level of sound can be expressed by comparing the sound's intensity to the intensity of a sound barely audible tot he human ear. The formula D = 10(log I - log I0) describes the loudness level of a sound. D, in decibels, where I is the intensity of the sound, in watts per meter^2, and I(0) is the intensity of a sound barely audible to the human ear. a. Express the formula so that the expression in parentheses is written as a single logarithm. b. Continued below...

1. anonymous

b. Use the form of the formula from part (a) to answer this question: If a sound has an intensity 100 times the intensity of a softer sound how much larger on the decibel scale is the loudness level of the more intense sound.

2. anonymous

My Answers. A. $D=10*(Log(\frac{ I }{ I _{0} }))$ B. D=20

3. anonymous

Logarithm is a confusing topic. I am also equally confuse about the concepts.

4. anonymous

Yes I know,, I just want to make sure I have these right before I turn them in...

5. anonymous

|dw:1357649064572:dw|

6. anonymous

Looks correct

7. anonymous

this is what i have D = 10log(100Io/Io) D = 10log(100) D = 10*2 D = 20

8. anonymous

so 20 is correct?

9. anonymous

yes

10. anonymous

thank you so much for checking! :-)

11. anonymous

welcome