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- anonymous

Please check this logarithm question...
The loudness level of sound can be expressed by comparing the sound's intensity to the intensity of a sound barely audible tot he human ear. The formula D = 10(log I - log I0) describes the loudness level of a sound. D, in decibels, where I is the intensity of the sound, in watts per meter^2, and I(0) is the intensity of a sound barely audible to the human ear.
a. Express the formula so that the expression in parentheses is written as a single logarithm.
b. Continued below...

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- anonymous

- chestercat

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- anonymous

b. Use the form of the formula from part (a) to answer this question: If a sound has an intensity 100 times the intensity of a softer sound how much larger on the decibel scale is the loudness level of the more intense sound.

- anonymous

My Answers.
A. \[D=10*(Log(\frac{ I }{ I _{0} }))\]
B. D=20

- anonymous

Logarithm is a confusing topic. I am also equally confuse about the concepts.

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- anonymous

Yes I know,, I just want to make sure I have these right before I turn them in...

- anonymous

|dw:1357649064572:dw|

- anonymous

Looks correct

- anonymous

this is what i have
D = 10log(100Io/Io)
D = 10log(100)
D = 10*2
D = 20

- anonymous

so 20 is correct?

- anonymous

yes

- anonymous

thank you so much for checking! :-)

- anonymous

welcome

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