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kymber
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An object is launched at 19.6 m/s from a height of 58.8 m. The equation for the height (h) in terms of time (t) is given by h(t) = 4.9t² +19.6t + 58.8. What is the object's maximum height?
 one year ago
 one year ago
kymber Group Title
An object is launched at 19.6 m/s from a height of 58.8 m. The equation for the height (h) in terms of time (t) is given by h(t) = 4.9t² +19.6t + 58.8. What is the object's maximum height?
 one year ago
 one year ago

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ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
Convert it to the vertex form (have you learned that yet?).
 one year ago

boings Group TitleBest ResponseYou've already chosen the best response.0
Try to find the roots using the quadratic formula, then take the value of t halfway in between the roots and plug in. I think that should work
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
Basically, the parabola opens downwards. So see here:\[4.9t^2 + 19.6t +58.8 = 4.9t(t  4) + 58.8\]
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
Hmm actually\[4.9t^2 + 19.6t + 58.8 = 4.9(t^2  4t) + 58.8\]\[= 4.9(t^2  4t + 4  4) + 58.8 = 4.9(t  2)^2 + 54.8\]
 one year ago

kymber Group TitleBest ResponseYou've already chosen the best response.2
@ParthKohli, I don't understand this at all! :( What does that mean? How did you get it? Am I supposed to solve for t?
 one year ago
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