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 2 years ago
An object is launched at 19.6 m/s from a height of 58.8 m. The equation for the height (h) in terms of time (t) is given by h(t) = 4.9t² +19.6t + 58.8. What is the object's maximum height?
 2 years ago
An object is launched at 19.6 m/s from a height of 58.8 m. The equation for the height (h) in terms of time (t) is given by h(t) = 4.9t² +19.6t + 58.8. What is the object's maximum height?

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ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.1Convert it to the vertex form (have you learned that yet?).

boings
 2 years ago
Best ResponseYou've already chosen the best response.0Try to find the roots using the quadratic formula, then take the value of t halfway in between the roots and plug in. I think that should work

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.1Basically, the parabola opens downwards. So see here:\[4.9t^2 + 19.6t +58.8 = 4.9t(t  4) + 58.8\]

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.1Hmm actually\[4.9t^2 + 19.6t + 58.8 = 4.9(t^2  4t) + 58.8\]\[= 4.9(t^2  4t + 4  4) + 58.8 = 4.9(t  2)^2 + 54.8\]

kymber
 2 years ago
Best ResponseYou've already chosen the best response.2@ParthKohli, I don't understand this at all! :( What does that mean? How did you get it? Am I supposed to solve for t?
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