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 one year ago
An object is launched at 19.6 m/s from a height of 58.8 m. The equation for the height (h) in terms of time (t) is given by h(t) = 4.9t² +19.6t + 58.8. What is the object's maximum height?
 one year ago
An object is launched at 19.6 m/s from a height of 58.8 m. The equation for the height (h) in terms of time (t) is given by h(t) = 4.9t² +19.6t + 58.8. What is the object's maximum height?

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ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1Convert it to the vertex form (have you learned that yet?).

boings
 one year ago
Best ResponseYou've already chosen the best response.0Try to find the roots using the quadratic formula, then take the value of t halfway in between the roots and plug in. I think that should work

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1Basically, the parabola opens downwards. So see here:\[4.9t^2 + 19.6t +58.8 = 4.9t(t  4) + 58.8\]

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1Hmm actually\[4.9t^2 + 19.6t + 58.8 = 4.9(t^2  4t) + 58.8\]\[= 4.9(t^2  4t + 4  4) + 58.8 = 4.9(t  2)^2 + 54.8\]

kymber
 one year ago
Best ResponseYou've already chosen the best response.2@ParthKohli, I don't understand this at all! :( What does that mean? How did you get it? Am I supposed to solve for t?
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