Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

kymber

  • one year ago

An object is launched at 19.6 m/s from a height of 58.8 m. The equation for the height (h) in terms of time (t) is given by h(t) = -4.9t² +19.6t + 58.8. What is the object's maximum height?

  • This Question is Closed
  1. ParthKohli
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Convert it to the vertex form (have you learned that yet?).

  2. boings
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Try to find the roots using the quadratic formula, then take the value of t half-way in between the roots and plug in. I think that should work

  3. ParthKohli
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Basically, the parabola opens downwards. So see here:\[-4.9t^2 + 19.6t +58.8 = -4.9t(t - 4) + 58.8\]

  4. ParthKohli
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Hmm actually\[-4.9t^2 + 19.6t + 58.8 = -4.9(t^2 - 4t) + 58.8\]\[= -4.9(t^2 - 4t + 4 - 4) + 58.8 = -4.9(t - 2)^2 + 54.8\]

  5. kymber
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    @ParthKohli, I don't understand this at all! :( What does that mean? How did you get it? Am I supposed to solve for t?

  6. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.