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BrittanyFrench
Group Title
please help!
if the diamter of the circle has endpoints at (2,4) and (3,8), what is the length of the radius of the circle?
 one year ago
 one year ago
BrittanyFrench Group Title
please help! if the diamter of the circle has endpoints at (2,4) and (3,8), what is the length of the radius of the circle?
 one year ago
 one year ago

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cwrw238 Group TitleBest ResponseYou've already chosen the best response.0
find the length of the line joining the 2 points and divide the answer by 2
 one year ago

BrittanyFrench Group TitleBest ResponseYou've already chosen the best response.1
Um, not really sure what that means
 one year ago

Argos Group TitleBest ResponseYou've already chosen the best response.0
Find the distance between the points and divide by 2
 one year ago

BrittanyFrench Group TitleBest ResponseYou've already chosen the best response.1
so that would bewhat around4ish
 one year ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.0
the formula for the length of a line joining (x1,y1) and (x2,y2) = sqrt [(x2x1) ^2 + y2y1)^2] which is the Pythagoras theorem
 one year ago

Argos Group TitleBest ResponseYou've already chosen the best response.0
dw:1357683394940:dw
 one year ago

BrittanyFrench Group TitleBest ResponseYou've already chosen the best response.1
ok well I got 2
 one year ago

Argos Group TitleBest ResponseYou've already chosen the best response.0
dw:1357683510146:dw
 one year ago

ashlynn143 Group TitleBest ResponseYou've already chosen the best response.1
hope this helps Use the distance formula to find the length of the diameter between these two points. d = √[ (23)^2 + (48)^2 ] d = √[ (5)^2 + (4)^2 ] d = √( 25 + 16 ) d = √( 41 ) = 6.40312424 = diameter. the radius is 1/2 the diameter. 6.40312424/2 = 3.20156212.
 one year ago

BrittanyFrench Group TitleBest ResponseYou've already chosen the best response.1
wow.. Hopefully that's correct lol that looks about right! Thanks!
 one year ago

ashlynn143 Group TitleBest ResponseYou've already chosen the best response.1
anytime
 one year ago
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