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swiftskier96
 2 years ago
Best ResponseYou've already chosen the best response.0How do you solve this?? N = 3,500e^(k * 9.5)

CalebBeavers
 2 years ago
Best ResponseYou've already chosen the best response.1There's two variables...

swiftskier96
 2 years ago
Best ResponseYou've already chosen the best response.0I know. Im supposed to solve for k. Does that help at least a little bit? @CalebBeavers

CalebBeavers
 2 years ago
Best ResponseYou've already chosen the best response.1Hmm, start off by dividing both sides by 3500

swiftskier96
 2 years ago
Best ResponseYou've already chosen the best response.0So it would be N/3,500 = e^9.5k? @CalebBeavers

CalebBeavers
 2 years ago
Best ResponseYou've already chosen the best response.1Yeah, now take natural log of both sides

swiftskier96
 2 years ago
Best ResponseYou've already chosen the best response.0So In(N/3,500) = 9.5k?

CalebBeavers
 2 years ago
Best ResponseYou've already chosen the best response.1Yep, now just divide by 9.5

swiftskier96
 2 years ago
Best ResponseYou've already chosen the best response.0So In(N/3,500)/9.5 = k?

swiftskier96
 2 years ago
Best ResponseYou've already chosen the best response.0But the questions says to Use the function to find the value of the boat after 9.5 years. (Not this question, the question on my assignment.) Is that the boat value?

CalebBeavers
 2 years ago
Best ResponseYou've already chosen the best response.1so it gives you the function N = 3,500e^(kt) ?

swiftskier96
 2 years ago
Best ResponseYou've already chosen the best response.0Well it didnt give me that but i asked the question earlier and someone said to use that equation.

CalebBeavers
 2 years ago
Best ResponseYou've already chosen the best response.1Hmmm. lets start over whats the original question and all the information it gives you?

swiftskier96
 2 years ago
Best ResponseYou've already chosen the best response.014. The exponential decay graph shows the expected depreciation for a new boat, selling for $3500, over 10 years. Write an exponential function for the graph. Use the function to find the value of the boat after 9.5 years. @CalebBeavers

CalebBeavers
 2 years ago
Best ResponseYou've already chosen the best response.1Hmm so \[\large f(t)=ae^{kt}\] use known information from the graph, say point (3,1500) the a is the value at the start so plug these in and solve for k \[1500=3500e^{3k}\] when you know k you can plug it back in to solve for the value at 9.5 years

swiftskier96
 2 years ago
Best ResponseYou've already chosen the best response.0So if i plugged in 9.5 it would look like 1500 = 3500e^(3 * 9.5)?

CalebBeavers
 2 years ago
Best ResponseYou've already chosen the best response.1No, we need to solve for k. t represents time, we know after 3 years it was 1500 so were plugging that in so we have one variable to solve for

swiftskier96
 2 years ago
Best ResponseYou've already chosen the best response.0We need to solve for e?

CalebBeavers
 2 years ago
Best ResponseYou've already chosen the best response.1e is eulers number, its a constant just solve for k in \[\large1500=3500e^{3k}\]

swiftskier96
 2 years ago
Best ResponseYou've already chosen the best response.0Oh ok. So i would have to divide each side by 3500 right? That would give me 3/7 = e^3k. Then take the inverse of each side which would give me In(3/7) = 3k right?

CalebBeavers
 2 years ago
Best ResponseYou've already chosen the best response.1Yep, now divide by 3

CalebBeavers
 2 years ago
Best ResponseYou've already chosen the best response.1ln(3/7)/3=k now you know k, plug it back in along with the time you want to know which is 9.5 \[f(t)=3500e^{(\ln(3/7)/3)9.5}\]

swiftskier96
 2 years ago
Best ResponseYou've already chosen the best response.0So is that my final answer? Or do i have to solve more of it?

swiftskier96
 2 years ago
Best ResponseYou've already chosen the best response.0@CalebBeavers I dont want to bug you, but i have to log off soon and i really need to know if thats my final answer or what more i have to do.

CalebBeavers
 2 years ago
Best ResponseYou've already chosen the best response.1My bad, i didnt even see the notification. if you plug the right hand side into a calculator it will give you the value of the boat after 9.5 years

swiftskier96
 2 years ago
Best ResponseYou've already chosen the best response.0I did 3/7 = 0.42857142857142857142857142857143 then divided that by 3 and that equaled 0.14285714285714285714285714285714. Then i multiplied it by 9.5 and got 1.3571428571428571428571428571429. Then i pressed the In button and got 0.3053816495511818454864425669865. Is that right? Oh wait! Then do i do 3500e? The only thing is i dont see an e button on my calculator.

CalebBeavers
 2 years ago
Best ResponseYou've already chosen the best response.1You should plug it all in at once. use this calculator and type it in like 3500e^((ln(3/7)/3)*9.5)) http://web2.0calc.com/

swiftskier96
 2 years ago
Best ResponseYou've already chosen the best response.0Im trying but its being stupid. Either that or im stupid. I typed it all in and it wont let me press the = sign. When i do press it, it wont solve it.

CalebBeavers
 2 years ago
Best ResponseYou've already chosen the best response.1Well it gives me 239.226

swiftskier96
 2 years ago
Best ResponseYou've already chosen the best response.0Ok. Sorry. My computers stupid... lol Thanks for the help and being super patient!!!
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