## anonymous 3 years ago what is the radius of the circle: (x-3)^2+(y+2)^2=14

1. anonymous

$r= \sqrt {14}$

2. anonymous

just compare it from standard equation of circle that is (x-a)^2+(x-b)^2=R^2

3. anonymous

here you go x^2 + y^2 = r^2. Since your equation says (x – 3)^2 + (y + 2)^2 = 14, 14 is the radius squared. Therefore, the radius of the circle for the second equation is the square root of 14, or 3.74165739.

4. anonymous

Thanks girl! I've got so many problems I'm trying to figure out! lol

5. anonymous

lol np