## BrittanyFrench what is the radius of the circle: (x-3)^2+(y+2)^2=14 one year ago one year ago

1. itsmylife

$r= \sqrt {14}$

2. itsmylife

just compare it from standard equation of circle that is (x-a)^2+(x-b)^2=R^2

3. ashlynn143

here you go x^2 + y^2 = r^2. Since your equation says (x – 3)^2 + (y + 2)^2 = 14, 14 is the radius squared. Therefore, the radius of the circle for the second equation is the square root of 14, or 3.74165739.

4. BrittanyFrench

Thanks girl! I've got so many problems I'm trying to figure out! lol

5. ashlynn143

lol np