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Spartan_Of_Ares

  • 3 years ago

can some one help me with 7 rational expressions?

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  1. Spartan_Of_Ares
    • 3 years ago
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    \[\frac{ x+2 }{ (x-4)^{2} }- \frac{ x }{x-4 }\] this is my first one

  2. Spartan_Of_Ares
    • 3 years ago
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    hey @Hero can you help me out?

  3. Hero
    • 3 years ago
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    Hint: Multiply the second fraction by (x-4)/(x-4)

  4. Spartan_Of_Ares
    • 3 years ago
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    \[\frac{ x^2-4 }{ x^2-16 }?\]

  5. Spartan_Of_Ares
    • 3 years ago
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    @Hero is this right?

  6. Hero
    • 3 years ago
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    No, it's not

  7. Spartan_Of_Ares
    • 3 years ago
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    how would i go about doing this?

  8. Hero
    • 3 years ago
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    I'm only going to show you this once.

  9. Hero
    • 3 years ago
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    \[\space\space\space\space\frac{x + 2}{(x - 4)^2} - \frac{x}{x-4}\]\[=\frac{x + 2}{(x - 4)^2} - \frac{x}{x-4} \times\frac{x-4}{x-4}\]\[=\frac{x + 2}{(x - 4)^2} - \frac{x(x-4)}{x-4(x-4)}\]\[=\frac{x + 2}{(x - 4)^2} - \frac{x^2-4x}{(x-4)^2}\]\[=\frac{(x + 2) - (x^2 - 4x)}{(x-4)^2}\]\[=\frac{x + 2 - x^2 + 4x}{(x-4)^2}\]\[=\frac{-x^2 + 4x + x + 2}{(x-4)^2}\]\[=\frac{-x^2 + 5x + 2}{(x-4)^2}\]\[=\frac{-(x^2 - 5x - 2)}{(x-4)^2}\]\[=-\frac{x^2 - 5x - 2}{(x-4)^2}\]

  10. Spartan_Of_Ares
    • 3 years ago
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    thanks allot for the help!

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