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can some one help me with 6 rational expressions?

Mathematics
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\[\frac{3}{ z-4 }+\frac{6 }{ z+3 }\]
what?
@Spartan_Of_Ares, I could have sworn I showed you how to simplify rational expressions.

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Other answers:

omggg help me please
i wanted to know if i did this right
spartan
yes
whats the thing is
@jevans17, post your own question
first i got \[\frac{ 3 }{ z-4 }\]\[\frac{ z+18 }{ (z+3)^2 }\] when multiplying
that came out wrong and jevans i have no clue what your talking about
Spartan, where's your teacher?
no my problem is not an equation
my teacher was sick today and we didn't really cover this
Well, you should wait until tomorrow and ask her.
\[\frac{ 3 }{ z-4 }+\frac{ z+18 }{ (z+3)^2 }\] this is how it came out i dont have her again until next tuesday
That's not what you're supposed to do.
ask your own questio jevans
You're supposed to do this: \[\frac{3}{z-4} \times 1 + \frac{6}{z + 3} \times 1\] \[\left(\frac{3}{z-4} \times \frac{z+3}{z+3}\right) + \left(\frac{6}{z+3} \times \frac{z-4}{z-4}\right)\]
heroo help me man
help me
@jevans17, where's your Geometry teacher?
i have none i really need help
I can't help fifteen people all at once.
pelase help me rea quick sir please
I still don't understand why you refuse to post your own question
thats my question sir its thee same
\[i got \frac{ 3z+9 }{ z^2-12 }+\frac{ 6z-24 }{ z^2-12 }\]
:{
lol he dumb
@jevans17, go to your own question
hero it is my own question its the same question
@Spartan_Of_Ares, you got the numerators correct.
on a scale of 1-10 how badly did i do that?
real bacl a 10
F
The denominators need work. See if you can understand this: \[(z - 4)(z + 3) = z(z + 3) - 4(z + 3) = z^2 + 3z - 4z - 12 = z^2 - z - 12\]
Hero help me pelase i dont have all day
GTFO!!
\[\space\space\space\space\space(z - 4)(z + 3) \\= z(z + 3) - 4(z + 3) \\= z^2 + 3z - 4z - 12 \\= z^2 - z - 12\]
Ares shut the f up and learn to multiply
@Spartan_Of_Ares, do you understand what I am posting?
yes i just didnt understand how you were getting a trinomial but that make sense
Hero how do i get someone else who can help me cause your no help at all
post your own question!
@jevans17, I refuse to help someone who infiltrates someone else's question.
I posted my own
ok so now ill have \[\frac{ 9z-15 }{z^2-z-12 }\] right?
@jevans17 Please refrain from posting your question inside someone else's question. That is just plain Disrespectful.
did i combine it right?
is that my final answer?
(っ⌒‿⌒)っ is it the final answer?(っ⌒‿⌒)っ
It is correct. That's why I gave you a medal
im sad its not an answer could it be
1 Attachment
Yes, that is it bro. Remember: (z - 4)(z + 3) = z^2 - z - 12
ok thanks for the help
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