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Spartan_Of_Ares

  • 2 years ago

can some one help me with 6 rational expressions?

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  1. Spartan_Of_Ares
    • 2 years ago
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    \[\frac{3}{ z-4 }+\frac{6 }{ z+3 }\]

  2. Spartan_Of_Ares
    • 2 years ago
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    what?

  3. Hero
    • 2 years ago
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    @Spartan_Of_Ares, I could have sworn I showed you how to simplify rational expressions.

  4. jevans17
    • 2 years ago
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    omggg help me please

  5. Spartan_Of_Ares
    • 2 years ago
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    i wanted to know if i did this right

  6. jevans17
    • 2 years ago
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    spartan

  7. Spartan_Of_Ares
    • 2 years ago
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    yes

  8. jevans17
    • 2 years ago
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    whats the thing is

  9. Hero
    • 2 years ago
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    @jevans17, post your own question

  10. Spartan_Of_Ares
    • 2 years ago
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    first i got \[\frac{ 3 }{ z-4 }\]\[\frac{ z+18 }{ (z+3)^2 }\] when multiplying

  11. Spartan_Of_Ares
    • 2 years ago
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    that came out wrong and jevans i have no clue what your talking about

  12. Hero
    • 2 years ago
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    Spartan, where's your teacher?

  13. jevans17
    • 2 years ago
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    no my problem is not an equation

  14. Spartan_Of_Ares
    • 2 years ago
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    my teacher was sick today and we didn't really cover this

  15. Hero
    • 2 years ago
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    Well, you should wait until tomorrow and ask her.

  16. Spartan_Of_Ares
    • 2 years ago
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    \[\frac{ 3 }{ z-4 }+\frac{ z+18 }{ (z+3)^2 }\] this is how it came out i dont have her again until next tuesday

  17. Hero
    • 2 years ago
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    That's not what you're supposed to do.

  18. Spartan_Of_Ares
    • 2 years ago
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    ask your own questio jevans

  19. Hero
    • 2 years ago
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    You're supposed to do this: \[\frac{3}{z-4} \times 1 + \frac{6}{z + 3} \times 1\] \[\left(\frac{3}{z-4} \times \frac{z+3}{z+3}\right) + \left(\frac{6}{z+3} \times \frac{z-4}{z-4}\right)\]

  20. jevans17
    • 2 years ago
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    heroo help me man

  21. jevans17
    • 2 years ago
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    help me

  22. Hero
    • 2 years ago
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    @jevans17, where's your Geometry teacher?

  23. jevans17
    • 2 years ago
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    i have none i really need help

  24. Hero
    • 2 years ago
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    I can't help fifteen people all at once.

  25. jevans17
    • 2 years ago
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    pelase help me rea quick sir please

  26. Hero
    • 2 years ago
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    I still don't understand why you refuse to post your own question

  27. jevans17
    • 2 years ago
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    thats my question sir its thee same

  28. Spartan_Of_Ares
    • 2 years ago
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    \[i got \frac{ 3z+9 }{ z^2-12 }+\frac{ 6z-24 }{ z^2-12 }\]

  29. Spartan_Of_Ares
    • 2 years ago
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    :{

  30. jevans17
    • 2 years ago
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    lol he dumb

  31. Hero
    • 2 years ago
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    @jevans17, go to your own question

  32. jevans17
    • 2 years ago
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    hero it is my own question its the same question

  33. Hero
    • 2 years ago
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    @Spartan_Of_Ares, you got the numerators correct.

  34. Spartan_Of_Ares
    • 2 years ago
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    on a scale of 1-10 how badly did i do that?

  35. jevans17
    • 2 years ago
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    real bacl a 10

  36. jevans17
    • 2 years ago
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    F

  37. Hero
    • 2 years ago
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    The denominators need work. See if you can understand this: \[(z - 4)(z + 3) = z(z + 3) - 4(z + 3) = z^2 + 3z - 4z - 12 = z^2 - z - 12\]

  38. jevans17
    • 2 years ago
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    Hero help me pelase i dont have all day

  39. Spartan_Of_Ares
    • 2 years ago
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    GTFO!!

  40. Hero
    • 2 years ago
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    \[\space\space\space\space\space(z - 4)(z + 3) \\= z(z + 3) - 4(z + 3) \\= z^2 + 3z - 4z - 12 \\= z^2 - z - 12\]

  41. jevans17
    • 2 years ago
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    Ares shut the f up and learn to multiply

  42. Hero
    • 2 years ago
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    @Spartan_Of_Ares, do you understand what I am posting?

  43. Spartan_Of_Ares
    • 2 years ago
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    yes i just didnt understand how you were getting a trinomial but that make sense

  44. jevans17
    • 2 years ago
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    Hero how do i get someone else who can help me cause your no help at all

  45. Spartan_Of_Ares
    • 2 years ago
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    post your own question!

  46. Hero
    • 2 years ago
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    @jevans17, I refuse to help someone who infiltrates someone else's question.

  47. jevans17
    • 2 years ago
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    I posted my own

  48. Spartan_Of_Ares
    • 2 years ago
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    ok so now ill have \[\frac{ 9z-15 }{z^2-z-12 }\] right?

  49. karatechopper
    • 2 years ago
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    @jevans17 Please refrain from posting your question inside someone else's question. That is just plain Disrespectful.

  50. Spartan_Of_Ares
    • 2 years ago
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    did i combine it right?

  51. Spartan_Of_Ares
    • 2 years ago
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    is that my final answer?

  52. Spartan_Of_Ares
    • 2 years ago
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    (っ⌒‿⌒)っ is it the final answer?(っ⌒‿⌒)っ

  53. Hero
    • 2 years ago
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    It is correct. That's why I gave you a medal

  54. Spartan_Of_Ares
    • 2 years ago
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    im sad its not an answer could it be

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  55. Hero
    • 2 years ago
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    Yes, that is it bro. Remember: (z - 4)(z + 3) = z^2 - z - 12

  56. Spartan_Of_Ares
    • 2 years ago
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    ok thanks for the help

  57. Spartan_Of_Ares
    • 2 years ago
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    (っ⌒‿⌒)っ(っ⌒‿⌒)っ(っ⌒‿⌒)っ(っ⌒‿⌒)っ(っ⌒‿⌒)っ(っ⌒‿⌒)っ(っ⌒‿⌒)っ(っ⌒‿⌒)っ(っ⌒‿⌒)っ

  58. Spartan_Of_Ares
    • 2 years ago
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