## AGummiBear55 2 years ago A group of 17 people are going to an amusement park. Adult tickets cost \$53.50 each and child tickets cost \$47.25 each. If the total cost for admission to the park is \$859.50, how many adults attended the amusement park? 7 8 9 10

1. ashlynn143

this is one expensive place but how many kids went so we can see how many adults went

2. AGummiBear55

That's my problem... It doesn't say... that's the whole question. :/

3. CalebBeavers

Set up two equations, one for the total number of people that went, and one for the total cost

4. ashlynn143

oh

5. ashlynn143

ok i will try no promises

6. AGummiBear55

@CalebBeavers What do you mean. @ashlynn143 It's okay, anything helps. (:

7. CalebBeavers

Call kids x and adults y so x+y=17 since 17 people went now try to make one for the cost

8. AGummiBear55

How would I make one for the cost if I don't know how many people went?

9. ashlynn143

17 people went

10. CalebBeavers

Use the variables...you know the price for each one and the total cost

11. ashlynn143

could this help y=adult x= child y(53.50) + x(47.25)

12. ashlynn143

@CalebBeavers ^^^^^

13. AGummiBear55

\$53.50x + 47.25y = 859.50 ???

14. CalebBeavers

Okay, adults can be x. thats right so now we have a system of equations x+y=17 53.50x+47.25y=859.50

15. ashlynn143

ok so now what do we do

16. AGummiBear55

??? I'm still confused. I'm sorry.. I'm horrible at math and it's been a long day. X(

17. ashlynn143

because we dont know the number of kids

18. AGummiBear55

I get what you have so far, but how do we get the number of adults who went?

19. CalebBeavers

Solve for y in the first equation

20. ashlynn143

i will try

21. AGummiBear55

How.. we don't know what x equals.

22. CalebBeavers

Solve for y in terms of x, just isolate y on the left side

23. AGummiBear55

okay, so... 47.25y=859.50-53.50x do I have that right so far or am I doing it wrong?

24. CalebBeavers

Solve for it in the first equation x+y=17 itll be much easier

25. AGummiBear55

okay so... y=17+x ... is that right so far?

26. AGummiBear55

*17-x

27. CalebBeavers

yep, now take 17-x and plug that in for y in the other equation

28. ashlynn143

i got to go sorry

29. AGummiBear55

@ashlynn143 it's okay. (:

30. AGummiBear55

What do you mean? like: 53.50x+47.25(17-x)=859.50 ???

31. CalebBeavers

Yes, now solve for x

32. AGummiBear55

How do I solve for x?

33. CalebBeavers

Algebra...just solve like normal theres only one variable now

34. AGummiBear55

yeah, but it's 17-x ... gah!! I'm confused. :(

35. CalebBeavers

Do you know how to solve an equation?

36. AGummiBear55

Yeah, but it's just confusing because there are no real numbers... like 17-x throws me off and gets me all confused.

37. AGummiBear55

Like if I were to solve for x, I'd have to isolate the x, but I don't know how in the world to do that because the 17-x is throwing me off and I'm confused on the whole problem now. :( :(

38. CalebBeavers

Distribute the 47.25 into the parentheses first

39. AGummiBear55

oh... okay, so... 53.50x + 803.25 + x = 859.50 ??? right? What next? (:

40. CalebBeavers

You didnt multiply the x.. 53.50x+803.25-47.25x=859.50

41. AGummiBear55

ohh... okay. duh. Alright. so 53.50x + 803.25 - 47.25x = 859.50.. now what?

42. CalebBeavers

combine like terms and subtract 803.25 from both sides

43. AGummiBear55

okay... so I get 57.

44. AGummiBear55

Now what?

45. CalebBeavers

thats not right

46. AGummiBear55

What? :( 53.50x + 503.25 = 859.50 6.25x + 503.25= 859.50 -503.25 6.25= 356.25 +6.25 = 57

47. CalebBeavers

6.25x=56.25 x=56.25/6.25

48. AGummiBear55

9? ?

49. AGummiBear55

(: YOU ARE AMAZING!! THANKS SO MUCH!!!! :D