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Mathhelp346

  • 3 years ago

log base 6 [log base 5 (log base 3 x)] = 0

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  1. Mathhelp346
    • 3 years ago
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    \[\log_{6} [\log_{5} (\log_{3}x) ]=0 \]

  2. anonymous
    • 3 years ago
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    pealing off one at a time, this tells you \[\log_5(\log_3(x))=1\] as a first step

  3. anonymous
    • 3 years ago
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    this in turn means \(\log_3(x)=5\)

  4. anonymous
    • 3 years ago
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    and finally this gives \(x=3^5\)

  5. Mathhelp346
    • 3 years ago
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    Wait, how did you know that \[\log_{5} (\log_{2} (x))=1\] ?

  6. Mathhelp346
    • 3 years ago
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    And what happened to\[\log_{6}\]

  7. Mertsj
    • 3 years ago
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    \[\log_{a}x=b \] means \[a ^{b}=x\]

  8. Mertsj
    • 3 years ago
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    The great one used that principle 3 times.

  9. Mathhelp346
    • 3 years ago
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    The great one...haha. :P

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