At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
Use Pythagoras. \[a^2 + b^2 = c^2\]
If they coincide, and relate, the triangle is a right angle.
so it would be 10^2 + 15^2 = what ??
If they don't it's either going to be acute or obtuse. For it to be acute, the hypotenuse of a right angle triangle is longer than your given hypotenuse which is 15 it is acute. If not, then it's obviously left with the only option to be obtuse.
c in that equation is the hypotenuse.
i dont get what numbers to put in which letters Im SO CONFUSED
the two shortest lengths of the triangle correspond with a^2 and b^2
the longest side which is 15, is the hypotenuse of the triangle.
okay so 7^2 + 10^2 = 149 So Now What
Now c^2= 149, am I right?
No c^2 = 225
Now all you have to do is Find c, which is around 12.2 and the longest length given in your question is 15. So the ideal right angle triangle with the two shortest sides you were given in the question has to have a hypotenuse of 12.2
225?....Are you drinking anything that's giving your problems with your thinking process?
well wouldnt it be 15^2 = 225 ? i dont know im confused
You're jumping ships at the moment. Right now c^2 is 149. You're thinking about the longest side given in your question.
Don't do that just yet. Stay at what you're doing right now. Take mathematics as a step by step process.
If you ruin the steps and just jump ahead two steps further, you're going to be in trouble if you do this in exams.
okay so were saying a+b = 149 and c = 149 //
No, \[a^2 + b^2= 149\]
c^2= 149. c=? HINT: Use your calculator.
okay i get it
Okay so, you end up with 12.2 (to the nearest dcp.) So for an ideal right angled triangle, your hypotenuse must have a length of 12.2
that's with the dimensions of 7, 10 that you were given in the question.
Now in the question, you have a triangle that has an hypotenuse of 15 instead of 12.2
That tells you that it's not a right angled triangle. Therefore your only options are that the triangle must be acute or obtuse.
You with me?
yea im with you sorry my nephew is being bad lol . keeep going
Okay. So if your given hypotenuse is less than 12.2 (eg. your dimensions were 7,10 and 11) then the triangle is acute.
But you were given dimensions of 7, 110 and 15.
Okay so its not acute or right. So it would be obtuse ?
so it's not acute, thus it must be obtuse.
okay can you explain how tho?
A triangle can aeither be acute,right angled or obtuse as seen from Aztec's proof it is neither right angled nor zcute so it must definitely be obtuse!!
but i need to explain how it is an obtuse in a shorter term
This question only gave you three options. You can't say it's neither acute, obtuse or right angled because that's not an option. That's an aspect you should also work on is knowing your options.
This question does not need any further analysis because you already solved it. If the question gave you dimensions of 7,10 and 11, you would do the same process. You would then find that the hypotenuse of the triangle (ie. side length of 11) is shorter than the ideal hypotenuse of a right angled triangle which is 12.2. Therefore you say that it's acute because it's shorter than the ideal hypotenuse of 12.2 in a right angled triangle
If you still want to understand more about this. This link gives you everything you need. http://www.algebra.com/algebra/homework/Triangles/Triangles.faq.question.457725.html