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ErinWeeks
 3 years ago
A triangle has side lengths 10, 15, and 7. Is the triangle acute, obtuse, or right? Explain
ErinWeeks
 3 years ago
A triangle has side lengths 10, 15, and 7. Is the triangle acute, obtuse, or right? Explain

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Use Pythagoras. \[a^2 + b^2 = c^2\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0If they coincide, and relate, the triangle is a right angle.

ErinWeeks
 3 years ago
Best ResponseYou've already chosen the best response.0so it would be 10^2 + 15^2 = what ??

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0If they don't it's either going to be acute or obtuse. For it to be acute, the hypotenuse of a right angle triangle is longer than your given hypotenuse which is 15 it is acute. If not, then it's obviously left with the only option to be obtuse.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0c in that equation is the hypotenuse.

ErinWeeks
 3 years ago
Best ResponseYou've already chosen the best response.0i dont get what numbers to put in which letters Im SO CONFUSED

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the two shortest lengths of the triangle correspond with a^2 and b^2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the longest side which is 15, is the hypotenuse of the triangle.

ErinWeeks
 3 years ago
Best ResponseYou've already chosen the best response.0okay so 7^2 + 10^2 = 149 So Now What

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Now c^2= 149, am I right?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Now all you have to do is Find c, which is around 12.2 and the longest length given in your question is 15. So the ideal right angle triangle with the two shortest sides you were given in the question has to have a hypotenuse of 12.2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0225?....Are you drinking anything that's giving your problems with your thinking process?

ErinWeeks
 3 years ago
Best ResponseYou've already chosen the best response.0well wouldnt it be 15^2 = 225 ? i dont know im confused

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You're jumping ships at the moment. Right now c^2 is 149. You're thinking about the longest side given in your question.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Don't do that just yet. Stay at what you're doing right now. Take mathematics as a step by step process.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0If you ruin the steps and just jump ahead two steps further, you're going to be in trouble if you do this in exams.

ErinWeeks
 3 years ago
Best ResponseYou've already chosen the best response.0okay so were saying a+b = 149 and c = 149 //

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0No, \[a^2 + b^2= 149\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0c^2= 149. c=? HINT: Use your calculator.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Okay so, you end up with 12.2 (to the nearest dcp.) So for an ideal right angled triangle, your hypotenuse must have a length of 12.2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0that's with the dimensions of 7, 10 that you were given in the question.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Now in the question, you have a triangle that has an hypotenuse of 15 instead of 12.2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0That tells you that it's not a right angled triangle. Therefore your only options are that the triangle must be acute or obtuse.

ErinWeeks
 3 years ago
Best ResponseYou've already chosen the best response.0yea im with you sorry my nephew is being bad lol . keeep going

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Okay. So if your given hypotenuse is less than 12.2 (eg. your dimensions were 7,10 and 11) then the triangle is acute.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0But you were given dimensions of 7, 110 and 15.

ErinWeeks
 3 years ago
Best ResponseYou've already chosen the best response.0Okay so its not acute or right. So it would be obtuse ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so it's not acute, thus it must be obtuse.

ErinWeeks
 3 years ago
Best ResponseYou've already chosen the best response.0okay can you explain how tho?

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.0A triangle can aeither be acute,right angled or obtuse as seen from Aztec's proof it is neither right angled nor zcute so it must definitely be obtuse!!

ErinWeeks
 3 years ago
Best ResponseYou've already chosen the best response.0but i need to explain how it is an obtuse in a shorter term

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0This question only gave you three options. You can't say it's neither acute, obtuse or right angled because that's not an option. That's an aspect you should also work on is knowing your options.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0This question does not need any further analysis because you already solved it. If the question gave you dimensions of 7,10 and 11, you would do the same process. You would then find that the hypotenuse of the triangle (ie. side length of 11) is shorter than the ideal hypotenuse of a right angled triangle which is 12.2. Therefore you say that it's acute because it's shorter than the ideal hypotenuse of 12.2 in a right angled triangle

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0If you still want to understand more about this. This link gives you everything you need. http://www.algebra.com/algebra/homework/Triangles/Triangles.faq.question.457725.html
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