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Kagome_gurl8

Use the Quadratic Formula to solve the equation. –x2 – x – 5 = 0

  • one year ago
  • one year ago

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  1. Kagome_gurl8
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    @Hero

    • one year ago
  2. Kagome_gurl8
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    -x^2*

    • one year ago
  3. Hero
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    \[–x^2 – x – 5 = 0\] 1st I would factor out -1: \[-(x^2 + x + 5) = 0\] Then divide both sides by -1 \[x^2 + x + 5 = 0\] Now I would use quadratic formula: \[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\] a = 1, b = 1, c = 5

    • one year ago
  4. Kagome_gurl8
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    Oh, thank you very much :)

    • one year ago
  5. Hero
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    Well, actually, hang on

    • one year ago
  6. Hero
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    When in doubt, compute the discriminant to see if this is even has any real solution

    • one year ago
  7. Hero
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    b^2 - 4ac = (1)^2 - 4(1)(5) = 1 - 20 = -19 No real solution

    • one year ago
  8. Kagome_gurl8
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    Thats what i got also, i wanted to make sure i was doing it right. :)

    • one year ago
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