## anonymous 3 years ago PLEASE HELP: SIMPLE HARMONIC MOTION A 0.77 kg object is attached to one end of a spring hanging vertically from a stand. The object is pushed upward 0.14m from the equilibrium position and released, causing the object to oscillate in simple harmonic motion with a frequency of 0.769Hz. Determine the period of the motion, angular frequency, spring constant, Displacement of the object after 0.13s, and Acceleration of the object after 0.13s

1. anonymous

Hi you can find $\omega$ from this :$\omega =2(pi)f$ and spring constant from this:$\omega=\sqrt({k/m})$

2. anonymous

@Yahoo! ..solve this question...

3. anonymous

4. anonymous

this solution is formula based..Explain it

5. anonymous

|dw:1357743076492:dw| |dw:1357743145369:dw| |dw:1357743232622:dw| |dw:1357743327039:dw|

6. anonymous

|dw:1357743398905:dw|

7. anonymous

Time period=1/linear frequency=1/f..

8. anonymous

|dw:1357749854411:dw| |dw:1357749904580:dw|

9. anonymous

@Taufique x = a sinwt.....ryt ?

10. anonymous

x=A*sin(wt-phi) and x=A*cos(wt-phi)..both will give u same result..