sjiwani
  • sjiwani
PLEASE HELP: SIMPLE HARMONIC MOTION A 0.77 kg object is attached to one end of a spring hanging vertically from a stand. The object is pushed upward 0.14m from the equilibrium position and released, causing the object to oscillate in simple harmonic motion with a frequency of 0.769Hz. Determine the period of the motion, angular frequency, spring constant, Displacement of the object after 0.13s, and Acceleration of the object after 0.13s
Physics
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
Hi you can find \[\omega \] from this :\[\omega =2(pi)f\] and spring constant from this:\[\omega=\sqrt({k/m})\]
anonymous
  • anonymous
@Yahoo! ..solve this question...
anonymous
  • anonymous
Probably..It is Already Solved...

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anonymous
  • anonymous
this solution is formula based..Explain it
anonymous
  • anonymous
|dw:1357743076492:dw| |dw:1357743145369:dw| |dw:1357743232622:dw| |dw:1357743327039:dw|
anonymous
  • anonymous
|dw:1357743398905:dw|
anonymous
  • anonymous
Time period=1/linear frequency=1/f..
anonymous
  • anonymous
|dw:1357749854411:dw| |dw:1357749904580:dw|
anonymous
  • anonymous
@Taufique x = a sinwt.....ryt ?
anonymous
  • anonymous
x=A*sin(wt-phi) and x=A*cos(wt-phi)..both will give u same result..

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