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sjiwani

  • one year ago

PLEASE HELP: SIMPLE HARMONIC MOTION A 0.77 kg object is attached to one end of a spring hanging vertically from a stand. The object is pushed upward 0.14m from the equilibrium position and released, causing the object to oscillate in simple harmonic motion with a frequency of 0.769Hz. Determine the period of the motion, angular frequency, spring constant, Displacement of the object after 0.13s, and Acceleration of the object after 0.13s

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  1. hosein
    • one year ago
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    Hi you can find \[\omega \] from this :\[\omega =2(pi)f\] and spring constant from this:\[\omega=\sqrt({k/m})\]

  2. Taufique
    • one year ago
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    @Yahoo! ..solve this question...

  3. Yahoo!
    • one year ago
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    Probably..It is Already Solved...

  4. Taufique
    • one year ago
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    this solution is formula based..Explain it

  5. Taufique
    • one year ago
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    |dw:1357743076492:dw| |dw:1357743145369:dw| |dw:1357743232622:dw| |dw:1357743327039:dw|

  6. Taufique
    • one year ago
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    |dw:1357743398905:dw|

  7. Taufique
    • one year ago
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    Time period=1/linear frequency=1/f..

  8. Taufique
    • one year ago
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    |dw:1357749854411:dw| |dw:1357749904580:dw|

  9. Yahoo!
    • one year ago
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    @Taufique x = a sinwt.....ryt ?

  10. Taufique
    • one year ago
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    x=A*sin(wt-phi) and x=A*cos(wt-phi)..both will give u same result..

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