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put x=0 to find Y intercept and Y=0 to find x
slope-intercept form? what does that look like? life already told you 90% of what to do. You just have to do it.
slope intercept form should look like y=mx+b.....where mis ur slope and b is ur y intercept, so:
|dw:1357718430099:dw| just look when x=0 your gonna get y intercept and when y=0 your gonna get x intercept
well, that's one of the 2! if you did it correctly. didnt check
x=0, -4y=12 y=-12/4=-3
similarly you can find for x
for finding x i would do the same as did for y?
exactly, just put y=0
x int = 2 y int is -3
# 1 to find the intercepts plug in y= 0 and solve for x 6x- 4y = 12 6x4* ( 0 ) = 12 plug in y = 0 6x-0 = 12 multiply -4 and 0 to get 0 . 6x=12 simplify x-= 12/6 divide both sides by 6 to isolate x x = 2 reduce , so the x - intercepts is ( 2, 0 ) ================= Now look here , y - intercept ,o find the intercepts plug in x= 0 and solve for y 6x-4y= 12 start with the given equation. 6* (0) -4y = 12 plug in x = 0 0-4y = 12 multiply 6 and 0 to get 0 . -4y = 12 simplify y= 12/-4 divide both sides by -4 to isolate y. y= -3 reduce. SO therefore the Y - intercepts is ( 0. -3 ) .
Graph of y=-3x+2 through the point (0,2) and we can see that the point lies on the line. Since we know the equation has a slope of -3 and goes through the point (0,2), this verifies our answer. If this helped , Medal me ..
would that be how i could find the slope intercept?
yes indeed , ..