anonymous
  • anonymous
how do I find the x and y intercepts of 6x-4y=12 and how do i the equation in slope-intercept form?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
put x=0 to find Y intercept and Y=0 to find x
NotTim
  • NotTim
slope-intercept form? what does that look like? life already told you 90% of what to do. You just have to do it.
anonymous
  • anonymous
slope intercept form should look like y=mx+b.....where mis ur slope and b is ur y intercept, so:

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NotTim
  • NotTim
rearranging then
anonymous
  • anonymous
y=3/2x-3
anonymous
  • anonymous
|dw:1357718430099:dw| just look when x=0 your gonna get y intercept and when y=0 your gonna get x intercept
NotTim
  • NotTim
well, that's one of the 2! if you did it correctly. didnt check
anonymous
  • anonymous
x=0, -4y=12 y=-12/4=-3
anonymous
  • anonymous
similarly you can find for x
anonymous
  • anonymous
for finding x i would do the same as did for y?
anonymous
  • anonymous
exactly, just put y=0
anonymous
  • anonymous
x int = 2 y int is -3
anonymous
  • anonymous
# 1 to find the intercepts plug in y= 0 and solve for x 6x- 4y = 12 6x4* ( 0 ) = 12 plug in y = 0 6x-0 = 12 multiply -4 and 0 to get 0 . 6x=12 simplify x-= 12/6 divide both sides by 6 to isolate x x = 2 reduce , so the x - intercepts is ( 2, 0 ) ================= Now look here , y - intercept ,o find the intercepts plug in x= 0 and solve for y 6x-4y= 12 start with the given equation. 6* (0) -4y = 12 plug in x = 0 0-4y = 12 multiply 6 and 0 to get 0 . -4y = 12 simplify y= 12/-4 divide both sides by -4 to isolate y. y= -3 reduce. SO therefore the Y - intercepts is ( 0. -3 ) .
anonymous
  • anonymous
Graph of y=-3x+2 through the point (0,2) and we can see that the point lies on the line. Since we know the equation has a slope of -3 and goes through the point (0,2), this verifies our answer. If this helped , Medal me ..
anonymous
  • anonymous
would that be how i could find the slope intercept?
anonymous
  • anonymous
yes indeed , ..
anonymous
  • anonymous
sweet

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