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## stephcanie 2 years ago how do I find the x and y intercepts of 6x-4y=12 and how do i the equation in slope-intercept form?

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1. itsmylife

put x=0 to find Y intercept and Y=0 to find x

2. NotTim

slope-intercept form? what does that look like? life already told you 90% of what to do. You just have to do it.

3. jump

slope intercept form should look like y=mx+b.....where mis ur slope and b is ur y intercept, so:

4. NotTim

rearranging then

5. jump

y=3/2x-3

6. itsmylife

|dw:1357718430099:dw| just look when x=0 your gonna get y intercept and when y=0 your gonna get x intercept

7. NotTim

well, that's one of the 2! if you did it correctly. didnt check

8. itsmylife

x=0, -4y=12 y=-12/4=-3

9. itsmylife

similarly you can find for x

10. stephcanie

for finding x i would do the same as did for y?

11. itsmylife

exactly, just put y=0

12. jump

x int = 2 y int is -3

13. _CharmingBri

# 1 to find the intercepts plug in y= 0 and solve for x 6x- 4y = 12 6x4* ( 0 ) = 12 plug in y = 0 6x-0 = 12 multiply -4 and 0 to get 0 . 6x=12 simplify x-= 12/6 divide both sides by 6 to isolate x x = 2 reduce , so the x - intercepts is ( 2, 0 ) ================= Now look here , y - intercept ,o find the intercepts plug in x= 0 and solve for y 6x-4y= 12 start with the given equation. 6* (0) -4y = 12 plug in x = 0 0-4y = 12 multiply 6 and 0 to get 0 . -4y = 12 simplify y= 12/-4 divide both sides by -4 to isolate y. y= -3 reduce. SO therefore the Y - intercepts is ( 0. -3 ) .

14. _CharmingBri

Graph of y=-3x+2 through the point (0,2) and we can see that the point lies on the line. Since we know the equation has a slope of -3 and goes through the point (0,2), this verifies our answer. If this helped , Medal me ..

15. stephcanie

would that be how i could find the slope intercept?

16. _CharmingBri

yes indeed , ..

17. stephcanie

sweet

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