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Azteck
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A truck is to be driven 200 km along a level highway at x km per hour. Petrol costs 8 cents per litre and is used at the rate of \[25+\frac{ x^2 }{ 112 }\] litres per hour. The driver receives 2 dollars per hour. What is the most economical speed (to the nearest km per hour and the cost of the trip
i) if there is no speed limit,
ii) if the speed must not exceed 60km per hour?
 one year ago
 one year ago
Azteck Group Title
A truck is to be driven 200 km along a level highway at x km per hour. Petrol costs 8 cents per litre and is used at the rate of \[25+\frac{ x^2 }{ 112 }\] litres per hour. The driver receives 2 dollars per hour. What is the most economical speed (to the nearest km per hour and the cost of the trip i) if there is no speed limit, ii) if the speed must not exceed 60km per hour?
 one year ago
 one year ago

This Question is Closed

Azteck Group TitleBest ResponseYou've already chosen the best response.1
Topic: Calculus Sub Topic: Maxima and Minima.
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
Is it 74.83 km/h?
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
\[C(x) = 0.08(25 + \frac{ x^{2} }{ 112 }) * \frac{ 200 }{ x } + 2(\frac{ 200 }{ x })\] This is the equation I came up with for Cost.
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
How did you do the first part?
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
sorry
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
let me rewrite that , (i used american units and accidentally wrote it in the wrong place)
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
The first thing we know is that the rate of petrol is $0.08/litre And the second thing we know is that the petrol is used at a rate of 25 + x^2/112 litre/h so \[0.08 \frac{ dollar}{ litre } * (25 + \frac{ x^{2} }{ 112 }) \frac{ litre }{ hour }\] Gives us the units dollars/hour
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
The only thing we need to know is how long the trip takes. We know speed = distance / time speed = x distance = 200 km time = t Therefore time, t = 200/x If we multiply what we have so far by (200/x) (which is in hours), then the hours unit cancels leaving an expression in dollars
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
So far, I'm up to: \[0.08*(25+\frac{ x^2 }{ 112 })\]
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
\[0.08 \frac{ dollar }{ litre } * (25 + \frac{ x^{2} }{ 112 }) \frac{ litre }{ hour } * \frac{ 200 }{ x } hours\]
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
So you get that, and do you then add: \[\frac{ 400 }{ x }\] for the money he receives per hour?
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
okay. Now I'm getting somewhere.
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
So do we differentiate that with respect to x?
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
Yes because C(x) is the cost evaluated at x. So we need to minimize cost by differentiating with respect to x.
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
Thanks for the assistance @LogicalApple . Appreciate it.
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
Not a problem
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
For the second part of the question, keep in mind that the point we evaluated in the first part was a minimum. Due to the nature of the hyperbola, you can consider it an absolute minimum whenever x > 0 This should help you answer the second part of the question.
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
Yeah I already finished the question.
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
Oh, nice
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
The hard part was what you did for me.
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
I did it on paper and I was like "hm.. I can't think in litres/gallon"
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
Ah, I did it again lol I mean litres/hour!
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
Well I'm going to close this and put up another question. Thanks again for helping me.
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
Hope you can help me again if you see fit to.
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
Good luck!
 one year ago
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