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 2 years ago
<Simultaneous equation>
y=2x, x(x+y)=53y^2
a solution would be helpful please, no idea how these things are solved
 2 years ago
<Simultaneous equation> y=2x, x(x+y)=53y^2 a solution would be helpful please, no idea how these things are solved

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Helper93
 2 years ago
Best ResponseYou've already chosen the best response.0You know that y=2x, so plug in 2x instead of y in the second equation and solve.

Matt71
 2 years ago
Best ResponseYou've already chosen the best response.0What's (2x)^2? Is it the long answer or like, the one with 2 numbers?

Matt71
 2 years ago
Best ResponseYou've already chosen the best response.0can't do it man, help me out here

Mertsj
 2 years ago
Best ResponseYou've already chosen the best response.2If y = 2x, then x = 2y. Replace each x with 2y

Matt71
 2 years ago
Best ResponseYou've already chosen the best response.0where do I go from 22y=53y^2?

Mertsj
 2 years ago
Best ResponseYou've already chosen the best response.2Put it in the standard form for a quadratic equation and then solve by factoring (if it will factor) or by the quadratic formula if it will not.

Mertsj
 2 years ago
Best ResponseYou've already chosen the best response.2Rearrange the equation so that it is equal to 0. Make the y^2 term positive.

Mertsj
 2 years ago
Best ResponseYou've already chosen the best response.2Also, it should be 42y not 22y

Helper93
 2 years ago
Best ResponseYou've already chosen the best response.0Actually, Mertsj is right, it's easier to replace x other than y.

Matt71
 2 years ago
Best ResponseYou've already chosen the best response.0could one of you dudes just give me the answer +solution? It's REALLY late

Mertsj
 2 years ago
Best ResponseYou've already chosen the best response.2\[(2y)(2y+y)=53y^2\] \[(2y)(2)=53y^2\] \[42y=53y^2\] \[3y^22y1=0\] \[(3y+1)(y1)=0\]

Mertsj
 2 years ago
Best ResponseYou've already chosen the best response.2Can you solve that for y?

Matt71
 2 years ago
Best ResponseYou've already chosen the best response.0how did 3y^22y1=0 become (3y+1)(y1)=0 ?

Helper93
 2 years ago
Best ResponseYou've already chosen the best response.0You can also use discriminant if you want.

Matt71
 2 years ago
Best ResponseYou've already chosen the best response.0thanks dudes, I'll try to figure this dang thing out

Matt71
 2 years ago
Best ResponseYou've already chosen the best response.0Sorry Helper Can't give more than one medal
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