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Matt71

  • 3 years ago

<Simultaneous equation> y=2-x, x(x+y)=5-3y^2 a solution would be helpful please, no idea how these things are solved

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  1. Helper93
    • 3 years ago
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    You know that y=2-x, so plug in 2-x instead of y in the second equation and solve.

  2. Matt71
    • 3 years ago
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    Hold on, lemme try

  3. Matt71
    • 3 years ago
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    What's (2-x)^2? Is it the long answer or like, the one with 2 numbers?

  4. Matt71
    • 3 years ago
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    can't do it man, help me out here

  5. Mertsj
    • 3 years ago
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    If y = 2-x, then x = 2-y. Replace each x with 2-y

  6. Matt71
    • 3 years ago
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    where do I go from 2-2y=5-3y^2?

  7. Mertsj
    • 3 years ago
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    Put it in the standard form for a quadratic equation and then solve by factoring (if it will factor) or by the quadratic formula if it will not.

  8. Matt71
    • 3 years ago
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    English man, English

  9. Mertsj
    • 3 years ago
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    Rearrange the equation so that it is equal to 0. Make the y^2 term positive.

  10. Mertsj
    • 3 years ago
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    Also, it should be 4-2y not 2-2y

  11. Matt71
    • 3 years ago
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    Oh

  12. Helper93
    • 3 years ago
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    Actually, Mertsj is right, it's easier to replace x other than y.

  13. Matt71
    • 3 years ago
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    Eh?

  14. Matt71
    • 3 years ago
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    could one of you dudes just give me the answer +solution? It's REALLY late

  15. Mertsj
    • 3 years ago
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    \[(2-y)(2-y+y)=5-3y^2\] \[(2-y)(2)=5-3y^2\] \[4-2y=5-3y^2\] \[3y^2-2y-1=0\] \[(3y+1)(y-1)=0\]

  16. Mertsj
    • 3 years ago
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    Can you solve that for y?

  17. Matt71
    • 3 years ago
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    waaaait

  18. Matt71
    • 3 years ago
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    how did 3y^2-2y-1=0 become (3y+1)(y-1)=0 ?

  19. Mertsj
    • 3 years ago
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    By factoring.

  20. Matt71
    • 3 years ago
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    what method?

  21. Helper93
    • 3 years ago
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    You can also use discriminant if you want.

  22. Mertsj
    • 3 years ago
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    Too many cooks.

  23. Matt71
    • 3 years ago
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    mmm, well

  24. Matt71
    • 3 years ago
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    thanks dudes, I'll try to figure this dang thing out

  25. Matt71
    • 3 years ago
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    Sorry Helper Can't give more than one medal

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