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Matt71

<Simultaneous equation> y=2-x, x(x+y)=5-3y^2 a solution would be helpful please, no idea how these things are solved

  • one year ago
  • one year ago

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  1. Helper93
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    You know that y=2-x, so plug in 2-x instead of y in the second equation and solve.

    • one year ago
  2. Matt71
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    Hold on, lemme try

    • one year ago
  3. Matt71
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    What's (2-x)^2? Is it the long answer or like, the one with 2 numbers?

    • one year ago
  4. Matt71
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    can't do it man, help me out here

    • one year ago
  5. Mertsj
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    If y = 2-x, then x = 2-y. Replace each x with 2-y

    • one year ago
  6. Matt71
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    where do I go from 2-2y=5-3y^2?

    • one year ago
  7. Mertsj
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    Put it in the standard form for a quadratic equation and then solve by factoring (if it will factor) or by the quadratic formula if it will not.

    • one year ago
  8. Matt71
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    English man, English

    • one year ago
  9. Mertsj
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    Rearrange the equation so that it is equal to 0. Make the y^2 term positive.

    • one year ago
  10. Mertsj
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    Also, it should be 4-2y not 2-2y

    • one year ago
  11. Matt71
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    Oh

    • one year ago
  12. Helper93
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    Actually, Mertsj is right, it's easier to replace x other than y.

    • one year ago
  13. Matt71
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    Eh?

    • one year ago
  14. Matt71
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    could one of you dudes just give me the answer +solution? It's REALLY late

    • one year ago
  15. Mertsj
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    \[(2-y)(2-y+y)=5-3y^2\] \[(2-y)(2)=5-3y^2\] \[4-2y=5-3y^2\] \[3y^2-2y-1=0\] \[(3y+1)(y-1)=0\]

    • one year ago
  16. Mertsj
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    Can you solve that for y?

    • one year ago
  17. Matt71
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    waaaait

    • one year ago
  18. Matt71
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    how did 3y^2-2y-1=0 become (3y+1)(y-1)=0 ?

    • one year ago
  19. Mertsj
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    By factoring.

    • one year ago
  20. Matt71
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    what method?

    • one year ago
  21. Helper93
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    You can also use discriminant if you want.

    • one year ago
  22. Mertsj
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    Too many cooks.

    • one year ago
  23. Matt71
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    mmm, well

    • one year ago
  24. Matt71
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    thanks dudes, I'll try to figure this dang thing out

    • one year ago
  25. Matt71
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    Sorry Helper Can't give more than one medal

    • one year ago
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