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Matt71
Group Title
<Simultaneous equation>
y=2x, x(x+y)=53y^2
a solution would be helpful please, no idea how these things are solved
 one year ago
 one year ago
Matt71 Group Title
<Simultaneous equation> y=2x, x(x+y)=53y^2 a solution would be helpful please, no idea how these things are solved
 one year ago
 one year ago

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Helper93 Group TitleBest ResponseYou've already chosen the best response.0
You know that y=2x, so plug in 2x instead of y in the second equation and solve.
 one year ago

Matt71 Group TitleBest ResponseYou've already chosen the best response.0
Hold on, lemme try
 one year ago

Matt71 Group TitleBest ResponseYou've already chosen the best response.0
What's (2x)^2? Is it the long answer or like, the one with 2 numbers?
 one year ago

Matt71 Group TitleBest ResponseYou've already chosen the best response.0
can't do it man, help me out here
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.2
If y = 2x, then x = 2y. Replace each x with 2y
 one year ago

Matt71 Group TitleBest ResponseYou've already chosen the best response.0
where do I go from 22y=53y^2?
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.2
Put it in the standard form for a quadratic equation and then solve by factoring (if it will factor) or by the quadratic formula if it will not.
 one year ago

Matt71 Group TitleBest ResponseYou've already chosen the best response.0
English man, English
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.2
Rearrange the equation so that it is equal to 0. Make the y^2 term positive.
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.2
Also, it should be 42y not 22y
 one year ago

Helper93 Group TitleBest ResponseYou've already chosen the best response.0
Actually, Mertsj is right, it's easier to replace x other than y.
 one year ago

Matt71 Group TitleBest ResponseYou've already chosen the best response.0
could one of you dudes just give me the answer +solution? It's REALLY late
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.2
\[(2y)(2y+y)=53y^2\] \[(2y)(2)=53y^2\] \[42y=53y^2\] \[3y^22y1=0\] \[(3y+1)(y1)=0\]
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.2
Can you solve that for y?
 one year ago

Matt71 Group TitleBest ResponseYou've already chosen the best response.0
how did 3y^22y1=0 become (3y+1)(y1)=0 ?
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.2
By factoring.
 one year ago

Matt71 Group TitleBest ResponseYou've already chosen the best response.0
what method?
 one year ago

Helper93 Group TitleBest ResponseYou've already chosen the best response.0
You can also use discriminant if you want.
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.2
Too many cooks.
 one year ago

Matt71 Group TitleBest ResponseYou've already chosen the best response.0
thanks dudes, I'll try to figure this dang thing out
 one year ago

Matt71 Group TitleBest ResponseYou've already chosen the best response.0
Sorry Helper Can't give more than one medal
 one year ago
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