dread907
4x2  2x  9 = 0



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dread907
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Used the quadratic equation to solve the question, and show all work.

baziham
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in ax^2 + bx+ c=0
x=(b + sqr( b^2  4ac))/(2a)
x=(b  sqr( b^2  4ac))/(2a)

Goten77
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dw:1357767295007:dw then it depends on how much they want it reduced...

baziham
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dw:1357760479660:dw

baziham
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dw:1357760552634:dw

baziham
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\[x=\frac{ 1\pm5\sqrt{2} }{ 4 }\]