## Pankey one year ago Help with 1a 6b

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1. van1234

I don't know if this is the fastest way, but here's what I would do: $A \sin(x+c) = A(sinx cosc + sinccosx)$ Since there already is a sinx - cosx, we know that c will be in 4th quadrant because sinc must be negative and cosc must be positive, and that cosc = sinc (ignoring the signs) This gives us $3\pi/4$ or $-\pi/4$ And since we have a common factor of $\sqrt{2}/2$ we need to make A to cancel that so A will = $\sqrt{2}$ And so we get: $\sqrt{2} \times (\sin(x+3\pi/4))$ or $\sqrt{2} \times (\sin(x-\pi/4))$