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1 Attachment
A. 668 m2; 704 m2 B. 645 m2; 740 m2 C. 668 m2; 740 m2 D. 645 m2; 812 m2
it gave me no question this is all im guessing find the area and something else!

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Other answers:

well, i can help you.. first you know that the are is the sum of the area of the sides, so you have a rectangle of area (23*12.04) (top view) + you have another rectangle of area (8*23) (back view)+ you have a bottom rectangle of (23*9)+ you have 2 triangles of area (8*9/2) (but are 2 triangles.. the net area of the 2 trianles will be (8*9))... at the end, :\[(23*12.04)+ (8*23)+(23*9)+(\frac{ 8*9 }{2 })+(\frac{ 8*9 }{2 })\approx 740 m\]
sorry m^2 xD
okay so thats the area? but now what else do i have to find?
@ankolix Try using \cdot instead of *.
so would it be a??
i think that the are without the triangles ;)
sorry: *area
im confused lol
so i was right its a?
sorry "C" option im lagging so hard :/
thank you so muchhhh ! you saved my lifee
medal ;D

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