Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

mathmate Group TitleBest ResponseYou've already chosen the best response.0
let y=cos(pi/12), then apply the double angle formula: cos^2(x)sin^2(x)=cos(2x) or, substituting sin^2(x)+cos^2(x)=1, 2cos^2(x)1=cos(2x) cos^2(x)=(1+cos(2x))/2 let x=pi/12 then cos^2(pi/12)=(1+cos(pi/6))/2 Since cos(pi/6) is known to be sqrt(3)/2, cos(pi/12)=sqrt((1+sqrt(3)/2)/2)
 one year ago

VeroZarate Group TitleBest ResponseYou've already chosen the best response.0
im sorry but thats not one of my options
 one year ago

VeroZarate Group TitleBest ResponseYou've already chosen the best response.0
i somehow have to use the sum and difference formulas
 one year ago

mathmate Group TitleBest ResponseYou've already chosen the best response.0
Are they in numerical values?
 one year ago

VeroZarate Group TitleBest ResponseYou've already chosen the best response.0
yes they all have sqrt6 and sqrt2 over 4 but with different signs +/
 one year ago

mathmate Group TitleBest ResponseYou've already chosen the best response.0
cos^2(x)sin^2(x)=cos(2x) is from the double angle formula.
 one year ago

VeroZarate Group TitleBest ResponseYou've already chosen the best response.0
how would you split pi/12? i think thats what i need to do?
 one year ago

mathmate Group TitleBest ResponseYou've already chosen the best response.0
You will need to evaluate each option to see if it evaluates to: sqrt((1+sqrt(3)/2)/2) which can be written as sqrt((2+sqrt(3)/4) or sqrt(2+sqrt(3))/2 Why don't you post the options if you're not sure?
 one year ago

VeroZarate Group TitleBest ResponseYou've already chosen the best response.0
ok i think i got it thanks!!
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.