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TNNG
 2 years ago
Find all solutions to the equation.
cos x = sin x
TNNG
 2 years ago
Find all solutions to the equation. cos x = sin x

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mathmate
 2 years ago
Best ResponseYou've already chosen the best response.1When in doubt, draw a sketch: dw:1357770541986:dw The sketch is for 0<=x <=2pi. The general solution requires the form x=.... +2k pi where k is an integer.

mathmate
 2 years ago
Best ResponseYou've already chosen the best response.1You will need to solve for sin(x)=cos(x) between 0 and 2pi. The same solution will be valid if you add 2k pi to the obtained solution. Are you able to find the solution between 0 and 2pi?

TNNG
 2 years ago
Best ResponseYou've already chosen the best response.0look is the answer pi/2 +n(pi)(0,+/1,+/ 2

BluFoot
 2 years ago
Best ResponseYou've already chosen the best response.0Looking at the unit circle is another way to do it if you've learned that. When are the cos and sin values identical?

TNNG
 2 years ago
Best ResponseYou've already chosen the best response.0I tried about everything what is the answer

cinar
 2 years ago
Best ResponseYou've already chosen the best response.0yes one solution is that..

TNNG
 2 years ago
Best ResponseYou've already chosen the best response.0ok thank you i think i get it now

TNNG
 2 years ago
Best ResponseYou've already chosen the best response.0the other is 7pi /4 + 2npi

BluFoot
 2 years ago
Best ResponseYou've already chosen the best response.0it should be pi/4 +2npi and 5pi/4 + 2npi

TNNG
 2 years ago
Best ResponseYou've already chosen the best response.0i dont have a answer like that it is just pi/4 +2npi and 7pi /4 + 2npi. the answer with 5pi/4 + 2npi is paired with 3pi/4 + 2npi

BluFoot
 2 years ago
Best ResponseYou've already chosen the best response.0I don't know what the question is exactly but the solution to sinx=cosx is definitely x=pi/4 +2npi and x=5pi/4 + 2npi

TNNG
 2 years ago
Best ResponseYou've already chosen the best response.0Find all solutions to the equation. cos x = sin x is the question they are asking

BluFoot
 2 years ago
Best ResponseYou've already chosen the best response.0Well then their answer is wrong!
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