anonymous
  • anonymous
Find all solutions to the equation. cos x = sin x
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
Doesn't make sense
mathmate
  • mathmate
When in doubt, draw a sketch: |dw:1357770541986:dw| The sketch is for 0<=x <=2pi. The general solution requires the form x=.... +2k pi where k is an integer.
anonymous
  • anonymous
still do not get it

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mathmate
  • mathmate
You will need to solve for sin(x)=cos(x) between 0 and 2pi. The same solution will be valid if you add 2k pi to the obtained solution. Are you able to find the solution between 0 and 2pi?
anonymous
  • anonymous
look is the answer pi/2 +n(pi)(0,+/-1,+/- 2
anonymous
  • anonymous
Looking at the unit circle is another way to do it if you've learned that. When are the cos and sin values identical?
anonymous
  • anonymous
I tried about everything what is the answer
anonymous
  • anonymous
|dw:1357780533732:dw|
anonymous
  • anonymous
so it is pi/2 + n(pi)
anonymous
  • anonymous
http://www.wolframalpha.com/input/?i=solve+cosx-sinx%3D0
anonymous
  • anonymous
yes one solution is that..
anonymous
  • anonymous
ok thank you i think i get it now
anonymous
  • anonymous
I meant pi/4+2npi
anonymous
  • anonymous
the other is 7pi /4 + 2npi
anonymous
  • anonymous
it should be pi/4 +2npi and 5pi/4 + 2npi
anonymous
  • anonymous
i dont have a answer like that it is just pi/4 +2npi and 7pi /4 + 2npi. the answer with 5pi/4 + 2npi is paired with 3pi/4 + 2npi
anonymous
  • anonymous
I don't know what the question is exactly but the solution to sinx=cosx is definitely x=pi/4 +2npi and x=5pi/4 + 2npi
anonymous
  • anonymous
Find all solutions to the equation. cos x = sin x is the question they are asking
anonymous
  • anonymous
Well then their answer is wrong!
mathmate
  • mathmate
|dw:1357774360119:dw|

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