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I just helped you with this question! If you were confused you should have said so instead of closing the question!
OK we had 2 equations. x+y = 56 and y = 8 + x do you know how to solve a system of equations?
srry i was having a conversation with a teacher and i have to have this done and completed
sorta but not really
I like comparison. In both equations, solve for y=. It's already done for you in the second. Then set the two equations equal to each other, eliminating the y and solve for x.
so just 8 + x
No because you have to solve for y in the first equation. You get x+y = 56 y = 56-x and y= 8 + x so 8+x = 56-x solve for x!
would i first minus eight to both sides?
x = 48 -x
Add x on both sides
ok so this gives me 48
i mean 2x = 48
ok now divide by 2
can u help me with a few more
I'll help you with 1 more but you should be starting to be able to recognize the pattern and figure out how to solve it by yourself
2.Salisbury High School decided to take their students on a field trip to a theme park. A total of 150 people went on the trip. Adults pay $45.00 for a ticket and students pay $28.50 for a ticket. How many students and how many adults went to the park if they paid a total of $4770?
Okay here the variables (x and y) are the number of adults and the number of students. So we can say x = number of adults y = number of students These are the 2 statements: 1. A total of 150 people went on the trip 2. they paid a total of $4770 Can you turn these into equations?
x + y = 150 x45.00 + y28.50 = 4770
Sorry was afk for a sec. Yes that's correct. Now use substitution to solve. Solve for x or y in the first equation and plug it into the second equation
im not sure how to do that
cause first one we did comparison
Let's solve for y in the first equation x+y = 150 y= 150-x Now plug it into the second 45x + 28.5y = 4770 45x + 28.5(150-x) = 4770 now expand and solve for x
umm ok ive never seen that done before now though
OK I have to go, good luck :)
oh ok thanks