Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

Viktoria17 Group TitleBest ResponseYou've already chosen the best response.0
\[y=2x3\]
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
Is there anything more to this question?
 one year ago

Viktoria17 Group TitleBest ResponseYou've already chosen the best response.0
\[y=x ^{2}2x3\]
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
Ah ok. Sometimes it's easier to work with completing a square by first bringing the constant term to the other side. Start with y + 3 = x^2  2x and we can go from there.
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
We added 3 to both sides, so the left side becomes y + 3. This step is not necessary, but it makes completing the square clearer.
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
You should subtract 2/2 on the right
 one year ago

Viktoria17 Group TitleBest ResponseYou've already chosen the best response.0
I dont udnerstand...
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
We started with this equation: \[y = x^{2}  2x  3\] Then, adding 3 to both sides (this is an optional step): \[y + 3 = x^{2}  2x\] Take the coefficient of the x term, divide it by 2, then square it. That would be (2/2)^2 = 1. So we add 1 to both sides. \[y + 3 + 1 = x^{2}  2x + 1\] \[y + 4 = x^{2}  2x + 1\] Notice how the right side factors into a square now: \[y + 4 = (x  1)^{2}\] Now we can subtract 4 from both sides to get a final solution: \[y = (x  1)^{2}  4\]
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.