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anonymous
 4 years ago
By looking at 0.36 (repeating decimal) like an infinite geometric sequence, convert it into a fraction.
anonymous
 4 years ago
By looking at 0.36 (repeating decimal) like an infinite geometric sequence, convert it into a fraction.

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you can do this a couple ways

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is it \(\overline{.36}\) ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I have the formula \[S _{n}=\frac{ a _{1}a_{1}r ^{n} }{ 1r }\] If that helps.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok one simple method is to call \(x=\overline{.36}\) so \(100x=36\overline{.36}\) subtract and get \(100xx=36\) so \[99x=36\] and therefore \[x=\frac{36}{99}=\frac{4}{11}\] but that might not be what you want

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@satellite73 hey, when you get a chance can you finish helping me with that problem we started? thanks :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if you want to use the formula you wrote above, then since you are summing an infinite geometric series omit the \(a_1r^n\) part and go with \[S=\frac{a_1}{1r}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh. I think I copied the formula down incorrectly...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Cuz I was looking through my notes and wondering how I got the answers with the a1r^n part

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah since \(r<1\) you have \(\lim_{n\to \infty}r^n=0\)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0in this case you can use \[a=\frac{36}{100}\] and \[r=\frac{1}{100}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0For reference, though, does that formula equal\[S_{n}= \frac{ a_{1}(1r ^{n)} }{ 1r }\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you get \[S=\overline{.36}=\frac{\frac{36}{100}}{1\frac{1}{100}}\] \[=\frac{\frac{36}{100}}{\frac{99}{100}}\] \[=\frac{36}{99}\] etc

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no that is a formula for a finite series infinite series is the one i wrote above

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@erin512 repost i cannot find it
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