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By looking at 0.36 (repeating decimal) like an infinite geometric sequence, convert it into a fraction.
 one year ago
 one year ago
By looking at 0.36 (repeating decimal) like an infinite geometric sequence, convert it into a fraction.
 one year ago
 one year ago

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satellite73Best ResponseYou've already chosen the best response.0
you can do this a couple ways
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
is it \(\overline{.36}\) ?
 one year ago

GrazesBest ResponseYou've already chosen the best response.0
I have the formula \[S _{n}=\frac{ a _{1}a_{1}r ^{n} }{ 1r }\] If that helps.
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
ok one simple method is to call \(x=\overline{.36}\) so \(100x=36\overline{.36}\) subtract and get \(100xx=36\) so \[99x=36\] and therefore \[x=\frac{36}{99}=\frac{4}{11}\] but that might not be what you want
 one year ago

erin512Best ResponseYou've already chosen the best response.0
@satellite73 hey, when you get a chance can you finish helping me with that problem we started? thanks :)
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
if you want to use the formula you wrote above, then since you are summing an infinite geometric series omit the \(a_1r^n\) part and go with \[S=\frac{a_1}{1r}\]
 one year ago

GrazesBest ResponseYou've already chosen the best response.0
Oh. I think I copied the formula down incorrectly...
 one year ago

GrazesBest ResponseYou've already chosen the best response.0
Cuz I was looking through my notes and wondering how I got the answers with the a1r^n part
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
yeah since \(r<1\) you have \(\lim_{n\to \infty}r^n=0\)
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
in this case you can use \[a=\frac{36}{100}\] and \[r=\frac{1}{100}\]
 one year ago

GrazesBest ResponseYou've already chosen the best response.0
For reference, though, does that formula equal\[S_{n}= \frac{ a_{1}(1r ^{n)} }{ 1r }\]
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
you get \[S=\overline{.36}=\frac{\frac{36}{100}}{1\frac{1}{100}}\] \[=\frac{\frac{36}{100}}{\frac{99}{100}}\] \[=\frac{36}{99}\] etc
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
no that is a formula for a finite series infinite series is the one i wrote above
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
@erin512 repost i cannot find it
 one year ago
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