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 one year ago
By looking at 0.36 (repeating decimal) like an infinite geometric sequence, convert it into a fraction.
 one year ago
By looking at 0.36 (repeating decimal) like an infinite geometric sequence, convert it into a fraction.

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satellite73
 one year ago
Best ResponseYou've already chosen the best response.0you can do this a couple ways

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0is it \(\overline{.36}\) ?

Grazes
 one year ago
Best ResponseYou've already chosen the best response.0I have the formula \[S _{n}=\frac{ a _{1}a_{1}r ^{n} }{ 1r }\] If that helps.

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0ok one simple method is to call \(x=\overline{.36}\) so \(100x=36\overline{.36}\) subtract and get \(100xx=36\) so \[99x=36\] and therefore \[x=\frac{36}{99}=\frac{4}{11}\] but that might not be what you want

erin512
 one year ago
Best ResponseYou've already chosen the best response.0@satellite73 hey, when you get a chance can you finish helping me with that problem we started? thanks :)

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0if you want to use the formula you wrote above, then since you are summing an infinite geometric series omit the \(a_1r^n\) part and go with \[S=\frac{a_1}{1r}\]

Grazes
 one year ago
Best ResponseYou've already chosen the best response.0Oh. I think I copied the formula down incorrectly...

Grazes
 one year ago
Best ResponseYou've already chosen the best response.0Cuz I was looking through my notes and wondering how I got the answers with the a1r^n part

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0yeah since \(r<1\) you have \(\lim_{n\to \infty}r^n=0\)

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0in this case you can use \[a=\frac{36}{100}\] and \[r=\frac{1}{100}\]

Grazes
 one year ago
Best ResponseYou've already chosen the best response.0For reference, though, does that formula equal\[S_{n}= \frac{ a_{1}(1r ^{n)} }{ 1r }\]

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0you get \[S=\overline{.36}=\frac{\frac{36}{100}}{1\frac{1}{100}}\] \[=\frac{\frac{36}{100}}{\frac{99}{100}}\] \[=\frac{36}{99}\] etc

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0no that is a formula for a finite series infinite series is the one i wrote above

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0@erin512 repost i cannot find it
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