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alexashea1997

  • one year ago

Choose the slope-intercept equation of the line that passes through the point (4, –6) and is parallel to y = –1/2x + 5. (4 points) y = –2x + 2 y = 2x – 14 y = 1/2x – 8 y = –1/2x – 4

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  1. ajprincess
    • one year ago
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    y=mx +c m-slope c-y_intercept For parallel lines the slopes are same. Does that hep @alexashea1997?

  2. alexashea1997
    • one year ago
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    kinda.

  3. ajprincess
    • one year ago
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    If u feel that u need a bit more help u can ask me.:) you knw the slope and a point is given. using both of them u can find c. y=mx+c -6=-(1/2)*(4)+c Find c. Then plug in the values of m and c in y=mx+c to find the equation

  4. alexashea1997
    • one year ago
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    thats better thanks!

  5. alexashea1997
    • one year ago
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    can you help me with more ?

  6. ajprincess
    • one year ago
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    ya sure

  7. alexashea1997
    • one year ago
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    17. Which equation below is not an equation that represents the graph shown below? https://www.connexus.com/content/media/456845-752011-21644-PM-1719707532.png y – 3 = 2(x – 6) y + 3 = (x + 6) 2y = x x – 2y = 0

  8. alexashea1997
    • one year ago
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    i think its either a or b

  9. ajprincess
    • one year ago
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    I am sorry. I am unable to view ur attachment. It asks for login

  10. alexashea1997
    • one year ago
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  11. alexashea1997
    • one year ago
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    can you see that ?

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