(b^4)^6 * (b^2)^4 Simplify ? i need help

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

(b^4)^6 * (b^2)^4 Simplify ? i need help

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

(b^4)^6=b^24 (b^2)^4=b^8 b^24*b^8 = b^32 When you have the form (a^x)^y... u multiply the exponents so a^(xy) When you have the form b^x*b^y, you add the exponents so b^(x+y)
ok so does the formula stay the same if the problem read (k^3d^5)^5 ? im getting a bit confused on this one
yes you "distribute" the ^5... so you get k^15 * d^25

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

you can't simplify further since you have 2 different variables
thanks so much :) could you help me with a area and dimensions problem?...i dont want the answer i just want to know how to set up the problem
I could try my best :)
Justin wants to use 188 ft of fencing to fence off the greatest possible rectangular area for a garden. how would i find what dimensions he should use and what the area would be
Is this a calculus question
yea i think so
Ok so you want to maximize the area of the rectangle. The area of a rectangle is A=b*L (area=base*length). We know the perimeter of a rectangle is 2(b+L)=188. Since you want to maximize A, you want to express A with only one variable. So, you use the perimeter equation above and solve, for say L, and substitute the expression for L into your Area formula. So now you have an equation A = ... (which only has one variable "b"). So, know you just differentiate your function and setting it equal to 0 to find the critical points. Make sure you only consider actual physical values (if you get a negative value, for example, ignore it since you can't have a negative length). So, then you evaluate your function A = ... at the critical points and determine which value gives the largest value for A. This will be your maximum area.
I hope that's clear :S
It's funny you ask this question because I have a review assignment for another class based on first year calculus and the problem I am attacking now is an optimization problem as well :P
Oh wait I partially answered the question... You are asking for the dimensions. So, the process I told you will let you find "b". So with that, you can plug is the value for b in the perimeter equation 2(b+L)=188 and solve for L to get the length
its very clear just hard to understand because i have ADD which makes it kind of hard to read everything without forgetting -_- im going to test it and post my answer can you tell me if im right?
Ok sure
i got 8,811 ft^2 ?
Um I got 2209
:/ i went wrong somewhere
If you think of it in a simple way, although this depends if your prof talked about it or not, but the greatest area rectangle you can get is always a square. So 188 = 4c (c = side of a square) so c = 47. So each side is 47 ft. The area of a square = c^2 = 47^2 = 2209
Do you know how u got 8811?
thats what i just got 47X47 47; 2,209 ft2 :) i went back over your steps..maths so hard !
Yay awesome :)!
one more favor ...can you help me simplify an expression? i pretty much got the rest
Ok sure
4x^2y^7 over 24x^3y^4
\[\frac{ 4x^2y^7 }{ 24x^3y^4 }=\frac{ 1x^{2-3}*y^{7-4} }{ 6 }=\frac{ x^{-1}*y^{3} }{ 6 }=\frac{ y^{3} }{ 6x }\]
THANKS SO MUCH! wish i could give you a million medals :)
hm ok the numbers look small but it says x^(2-3) in the second "="
:) No problem!

Not the answer you are looking for?

Search for more explanations.

Ask your own question