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kirbykirby Group TitleBest ResponseYou've already chosen the best response.1
(b^4)^6=b^24 (b^2)^4=b^8 b^24*b^8 = b^32 When you have the form (a^x)^y... u multiply the exponents so a^(xy) When you have the form b^x*b^y, you add the exponents so b^(x+y)
 one year ago

Tony.M Group TitleBest ResponseYou've already chosen the best response.0
ok so does the formula stay the same if the problem read (k^3d^5)^5 ? im getting a bit confused on this one
 one year ago

kirbykirby Group TitleBest ResponseYou've already chosen the best response.1
yes you "distribute" the ^5... so you get k^15 * d^25
 one year ago

kirbykirby Group TitleBest ResponseYou've already chosen the best response.1
you can't simplify further since you have 2 different variables
 one year ago

Tony.M Group TitleBest ResponseYou've already chosen the best response.0
thanks so much :) could you help me with a area and dimensions problem?...i dont want the answer i just want to know how to set up the problem
 one year ago

kirbykirby Group TitleBest ResponseYou've already chosen the best response.1
I could try my best :)
 one year ago

Tony.M Group TitleBest ResponseYou've already chosen the best response.0
Justin wants to use 188 ft of fencing to fence off the greatest possible rectangular area for a garden. how would i find what dimensions he should use and what the area would be
 one year ago

kirbykirby Group TitleBest ResponseYou've already chosen the best response.1
Is this a calculus question
 one year ago

Tony.M Group TitleBest ResponseYou've already chosen the best response.0
yea i think so
 one year ago

kirbykirby Group TitleBest ResponseYou've already chosen the best response.1
Ok so you want to maximize the area of the rectangle. The area of a rectangle is A=b*L (area=base*length). We know the perimeter of a rectangle is 2(b+L)=188. Since you want to maximize A, you want to express A with only one variable. So, you use the perimeter equation above and solve, for say L, and substitute the expression for L into your Area formula. So now you have an equation A = ... (which only has one variable "b"). So, know you just differentiate your function and setting it equal to 0 to find the critical points. Make sure you only consider actual physical values (if you get a negative value, for example, ignore it since you can't have a negative length). So, then you evaluate your function A = ... at the critical points and determine which value gives the largest value for A. This will be your maximum area.
 one year ago

kirbykirby Group TitleBest ResponseYou've already chosen the best response.1
I hope that's clear :S
 one year ago

kirbykirby Group TitleBest ResponseYou've already chosen the best response.1
It's funny you ask this question because I have a review assignment for another class based on first year calculus and the problem I am attacking now is an optimization problem as well :P
 one year ago

kirbykirby Group TitleBest ResponseYou've already chosen the best response.1
Oh wait I partially answered the question... You are asking for the dimensions. So, the process I told you will let you find "b". So with that, you can plug is the value for b in the perimeter equation 2(b+L)=188 and solve for L to get the length
 one year ago

Tony.M Group TitleBest ResponseYou've already chosen the best response.0
its very clear just hard to understand because i have ADD which makes it kind of hard to read everything without forgetting _ im going to test it and post my answer can you tell me if im right?
 one year ago

kirbykirby Group TitleBest ResponseYou've already chosen the best response.1
Ok sure
 one year ago

Tony.M Group TitleBest ResponseYou've already chosen the best response.0
i got 8,811 ft^2 ?
 one year ago

kirbykirby Group TitleBest ResponseYou've already chosen the best response.1
Um I got 2209
 one year ago

Tony.M Group TitleBest ResponseYou've already chosen the best response.0
:/ i went wrong somewhere
 one year ago

kirbykirby Group TitleBest ResponseYou've already chosen the best response.1
If you think of it in a simple way, although this depends if your prof talked about it or not, but the greatest area rectangle you can get is always a square. So 188 = 4c (c = side of a square) so c = 47. So each side is 47 ft. The area of a square = c^2 = 47^2 = 2209
 one year ago

kirbykirby Group TitleBest ResponseYou've already chosen the best response.1
Do you know how u got 8811?
 one year ago

Tony.M Group TitleBest ResponseYou've already chosen the best response.0
thats what i just got 47X47 47; 2,209 ft2 :) i went back over your steps..maths so hard !
 one year ago

kirbykirby Group TitleBest ResponseYou've already chosen the best response.1
Yay awesome :)!
 one year ago

Tony.M Group TitleBest ResponseYou've already chosen the best response.0
one more favor ...can you help me simplify an expression? i pretty much got the rest
 one year ago

kirbykirby Group TitleBest ResponseYou've already chosen the best response.1
Ok sure
 one year ago

Tony.M Group TitleBest ResponseYou've already chosen the best response.0
4x^2y^7 over 24x^3y^4
 one year ago

kirbykirby Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{ 4x^2y^7 }{ 24x^3y^4 }=\frac{ 1x^{23}*y^{74} }{ 6 }=\frac{ x^{1}*y^{3} }{ 6 }=\frac{ y^{3} }{ 6x }\]
 one year ago

Tony.M Group TitleBest ResponseYou've already chosen the best response.0
THANKS SO MUCH! wish i could give you a million medals :)
 one year ago

kirbykirby Group TitleBest ResponseYou've already chosen the best response.1
hm ok the numbers look small but it says x^(23) in the second "="
 one year ago

kirbykirby Group TitleBest ResponseYou've already chosen the best response.1
:) No problem!
 one year ago
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