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baldymcgee6

  • 3 years ago

Integration by parts...

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  1. baldymcgee6
    • 3 years ago
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    |dw:1357797059876:dw|

  2. Fazeelayaz
    • 3 years ago
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    is it x*2 or x^2-------

  3. Fazeelayaz
    • 3 years ago
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    boy that's qiute long

  4. hartnn
    • 3 years ago
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    is it specifically asked to integrate by parts ??? because there is an easy way out...

  5. hartnn
    • 3 years ago
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    by putting u=x^2

  6. baldymcgee6
    • 3 years ago
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    no, I just assumed, because thats what we are studying :)

  7. baldymcgee6
    • 3 years ago
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    i'll try that subtitution

  8. hartnn
    • 3 years ago
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    then i suggest don't use by parts, put u=x^2 and find du=... it becomes so simple then

  9. baldymcgee6
    • 3 years ago
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    |dw:1357797312830:dw|

  10. baldymcgee6
    • 3 years ago
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    |dw:1357797408136:dw|

  11. hartnn
    • 3 years ago
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    yes, now its correct.

  12. baldymcgee6
    • 3 years ago
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    but what is the integral of 2^u?

  13. hartnn
    • 3 years ago
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    its a standard integral.

  14. hartnn
    • 3 years ago
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    2^u/ log 2

  15. baldymcgee6
    • 3 years ago
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    okkkk, thanks once again hartnn, haven't been on in a while.. Nice picture :)

  16. Fazeelayaz
    • 3 years ago
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    u r a genious hartn

  17. hartnn
    • 3 years ago
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    its not mine :P welcome ^_^

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