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angelwings996
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Couple of Math questions, please help!
1. What is the solution of the equation?
sqrt(2x  10)  5 = x
2. What is the simplest form of the radical expression?
3*cube root(2a)  6*cube root(2a)
3. Rewrite ^n sqrt(x^m) using a rational expression
 one year ago
 one year ago
angelwings996 Group Title
Couple of Math questions, please help! 1. What is the solution of the equation? sqrt(2x  10)  5 = x 2. What is the simplest form of the radical expression? 3*cube root(2a)  6*cube root(2a) 3. Rewrite ^n sqrt(x^m) using a rational expression
 one year ago
 one year ago

This Question is Closed

angelwings996 Group TitleBest ResponseYou've already chosen the best response.0
For Number 2\[3\sqrt[3]{2a}  6\sqrt[3]{2a}\]
 one year ago

angelwings996 Group TitleBest ResponseYou've already chosen the best response.0
For number 3 \[\sqrt[n]{x ^{m}}\]
 one year ago

completeidiot Group TitleBest ResponseYou've already chosen the best response.0
number 1 move the 5 over to the other side square both sides expand solve for zero on one side factor solve for x
 one year ago

completeidiot Group TitleBest ResponseYou've already chosen the best response.0
number 2 use the distribution property of multiplication but backwards
 one year ago

sammi904 Group TitleBest ResponseYou've already chosen the best response.0
Part 1: Solve the following quadratic equation using one of the methods listed below. Part 2: Using complete sentences, explain why you chose the method you used. Equation: 0 = x2 + 6x + 3 Methods: Completing the Square Factoring Quadratic Formula Graphing can someone help?
 one year ago

angelwings996 Group TitleBest ResponseYou've already chosen the best response.0
@sammi904 Why do I need to explain the methods I used ?
 one year ago

completeidiot Group TitleBest ResponseYou've already chosen the best response.0
number 3 \[\sqrt[n]{x}=x^{\frac{1}{n}}\]
 one year ago

angelwings996 Group TitleBest ResponseYou've already chosen the best response.0
@completeidiot so far for number 1, I got \[2x + 13 = 5x ^{2}\]
 one year ago

completeidiot Group TitleBest ResponseYou've already chosen the best response.0
you screwed up somewhere please show me steps
 one year ago

angelwings996 Group TitleBest ResponseYou've already chosen the best response.0
Oh I think I get what I did wrong. I times 5 with x instead of adding it so it would be \[2x + 10 = (x + 5)^{2}\] Right?
 one year ago

syhna Group TitleBest ResponseYou've already chosen the best response.1
2x10 = (x+5)^2 2x10 = x^2 + 10x + 25 0 = x^2 + 8x + 35
 one year ago

angelwings996 Group TitleBest ResponseYou've already chosen the best response.0
Okay, but how would you find the solution of the equation? @syhna
 one year ago

completeidiot Group TitleBest ResponseYou've already chosen the best response.0
Completing the Square Factoring Quadratic Formula your pick
 one year ago

angelwings996 Group TitleBest ResponseYou've already chosen the best response.0
Okay, I'll use the Quadratic Formula so A = 1, B = 10 and C = 25 correct?
 one year ago

completeidiot Group TitleBest ResponseYou've already chosen the best response.0
no, look at syhna's steps
 one year ago

angelwings996 Group TitleBest ResponseYou've already chosen the best response.0
Ohh sorry I was looking at the wrong one. A = 1 B = 8 and C = 35
 one year ago

angelwings996 Group TitleBest ResponseYou've already chosen the best response.0
Okay, I get number 1 now, what about number 2 ?
 one year ago

completeidiot Group TitleBest ResponseYou've already chosen the best response.0
i suggest factoring, for the practice
 one year ago

angelwings996 Group TitleBest ResponseYou've already chosen the best response.0
I'm not good at factoring at all, so that's why I am stuck
 one year ago

completeidiot Group TitleBest ResponseYou've already chosen the best response.0
actually, yes use quadratic formula cause i dont think you can factor it
 one year ago

angelwings996 Group TitleBest ResponseYou've already chosen the best response.0
How would I figure out what A, B, and C is?
 one year ago

syhna Group TitleBest ResponseYou've already chosen the best response.1
can #2 be subtracted ? i dont honestly get it
 one year ago

completeidiot Group TitleBest ResponseYou've already chosen the best response.0
ax^2+bx+c=0
 one year ago

angelwings996 Group TitleBest ResponseYou've already chosen the best response.0
@completeidiot I'm not sure how to identify a, b, and c in the equation \[3\sqrt[3]{2a}  6\sqrt[3]{2a}\]
 one year ago

completeidiot Group TitleBest ResponseYou've already chosen the best response.0
oh for number 2 i said use distribution property of multiplication but in reverse
 one year ago

completeidiot Group TitleBest ResponseYou've already chosen the best response.0
essentially the same as factoring
 one year ago

angelwings996 Group TitleBest ResponseYou've already chosen the best response.0
That's what I was asking lol. What do yu mean in reverse?
 one year ago

completeidiot Group TitleBest ResponseYou've already chosen the best response.0
a(b+c)= ab+ac in reverse would be pulling something out de+df=d(e+f)
 one year ago

angelwings996 Group TitleBest ResponseYou've already chosen the best response.0
Couldn't I cancel out 2a or no
 one year ago

syhna Group TitleBest ResponseYou've already chosen the best response.1
can this be \[\sqrt[3]{2a} = 2a ^{3}\] ?
 one year ago

angelwings996 Group TitleBest ResponseYou've already chosen the best response.0
It would actually be \[2a ^{1/3}\]
 one year ago

completeidiot Group TitleBest ResponseYou've already chosen the best response.0
no it would be 1/3 not 3 and you're missing a parenthesis
 one year ago

syhna Group TitleBest ResponseYou've already chosen the best response.1
a i see complete _ what you said a while ago about the reverse factoring then the prob should be equated to 0?
 one year ago

angelwings996 Group TitleBest ResponseYou've already chosen the best response.0
For the equation that you gave me @completeidiot de + df = d(e + f), would d be 2a ?
 one year ago

syhna Group TitleBest ResponseYou've already chosen the best response.1
so cube of a times (3 6) ????
 one year ago

angelwings996 Group TitleBest ResponseYou've already chosen the best response.0
@syhna How did you get that? Did you just substitute them into the equation completeidiot gave us?
 one year ago

completeidiot Group TitleBest ResponseYou've already chosen the best response.0
yes syhna
 one year ago

syhna Group TitleBest ResponseYou've already chosen the best response.1
the two terms had cuberoot of a
 one year ago

angelwings996 Group TitleBest ResponseYou've already chosen the best response.0
Oh so the answer for #2 is what you got?
 one year ago

syhna Group TitleBest ResponseYou've already chosen the best response.1
so it is 3(cube of 2a)? i think its just the same if we subtracted it
 one year ago

angelwings996 Group TitleBest ResponseYou've already chosen the best response.0
Yeah, that's what I was thinking that if I had subtracted it I would of got what you came up with because at first I subtracted it and came up with that but wasn't sure if it was right
 one year ago

angelwings996 Group TitleBest ResponseYou've already chosen the best response.0
Okay, last question, what would I do for #3 ?
 one year ago

completeidiot Group TitleBest ResponseYou've already chosen the best response.0
you're allowed to have improper fractions as exponents
 one year ago

angelwings996 Group TitleBest ResponseYou've already chosen the best response.0
Okay, I know you told me it was \[\sqrt[n]{x} = x ^{1/n}\] Is this an equation or the answer
 one year ago

angelwings996 Group TitleBest ResponseYou've already chosen the best response.0
@completeidiot
 one year ago

completeidiot Group TitleBest ResponseYou've already chosen the best response.0
thats a general rule of thumbs
 one year ago

completeidiot Group TitleBest ResponseYou've already chosen the best response.0
think of it as x^1
 one year ago

completeidiot Group TitleBest ResponseYou've already chosen the best response.0
now replace the 1 with m
 one year ago

angelwings996 Group TitleBest ResponseYou've already chosen the best response.0
Okay so it would be \[x ^{m/n} ?\]
 one year ago

angelwings996 Group TitleBest ResponseYou've already chosen the best response.0
Okay, could you go over my answer for number 1 really quick ?
 one year ago

angelwings996 Group TitleBest ResponseYou've already chosen the best response.0
The Quadratic formua is \[x = \frac{ b \pm \sqrt{b ^{2}  4ac} }{ 2a }\] right ?
 one year ago

syhna Group TitleBest ResponseYou've already chosen the best response.1
yeah i guess
 one year ago

angelwings996 Group TitleBest ResponseYou've already chosen the best response.0
Okay so I plugged it in nd got \[x = \frac{ 8 \pm \sqrt{76} }{ 2 }\] after simplifying everything
 one year ago

syhna Group TitleBest ResponseYou've already chosen the best response.1
in no 1 i dont think im right but i used completing the square and got \[4\pm \sqrt{19}\]
 one year ago

completeidiot Group TitleBest ResponseYou've already chosen the best response.0
its an imaginary answer but its still an answer
 one year ago

completeidiot Group TitleBest ResponseYou've already chosen the best response.0
either that or syhna messed up in his calcualtions
 one year ago

angelwings996 Group TitleBest ResponseYou've already chosen the best response.0
Wait, so mine was correct ? Or no
 one year ago

completeidiot Group TitleBest ResponseYou've already chosen the best response.0
dunno, didnt actually do any of the problems
 one year ago

syhna Group TitleBest ResponseYou've already chosen the best response.1
35 =x^2 + 8x 35 + 16 = x^2 + 8x + 16 19 = sqrt(x+4) sqrt(19) = x + 4 \[4\pm \sqrt{19}\] = x this is what i did.. dunno where i messed up
 one year ago

angelwings996 Group TitleBest ResponseYou've already chosen the best response.0
I'm not sure either, but thanks for trying to do the work with me! You were alot of help
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.0
\[x=4\pm\sqrt{19} = 4\pm i \sqrt{19} \] is correct
 one year ago
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