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angelwings996

Couple of Math questions, please help! 1. What is the solution of the equation? sqrt(2x - 10) - 5 = x 2. What is the simplest form of the radical expression? 3*cube root(2a) - 6*cube root(2a) 3. Rewrite ^n sqrt(x^m) using a rational expression

  • one year ago
  • one year ago

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  1. angelwings996
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    For Number 2\[3\sqrt[3]{2a} - 6\sqrt[3]{2a}\]

    • one year ago
  2. angelwings996
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    For number 3 \[\sqrt[n]{x ^{m}}\]

    • one year ago
  3. completeidiot
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    number 1- move the 5 over to the other side square both sides expand solve for zero on one side factor solve for x

    • one year ago
  4. completeidiot
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    number 2- use the distribution property of multiplication but backwards

    • one year ago
  5. sammi904
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    Part 1: Solve the following quadratic equation using one of the methods listed below. Part 2: Using complete sentences, explain why you chose the method you used. Equation: 0 = x2 + 6x + 3 Methods: Completing the Square Factoring Quadratic Formula Graphing can someone help?

    • one year ago
  6. angelwings996
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    @sammi904 Why do I need to explain the methods I used ?

    • one year ago
  7. completeidiot
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    number 3 \[\sqrt[n]{x}=x^{\frac{1}{n}}\]

    • one year ago
  8. angelwings996
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    @completeidiot so far for number 1, I got \[2x + 13 = 5x ^{2}\]

    • one year ago
  9. completeidiot
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    you screwed up somewhere please show me steps

    • one year ago
  10. angelwings996
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    Oh I think I get what I did wrong. I times 5 with x instead of adding it so it would be \[2x + 10 = (x + 5)^{2}\] Right?

    • one year ago
  11. syhna
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    2x-10 = (x+5)^2 2x-10 = x^2 + 10x + 25 0 = x^2 + 8x + 35

    • one year ago
  12. angelwings996
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    Okay, but how would you find the solution of the equation? @syhna

    • one year ago
  13. completeidiot
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    Completing the Square Factoring Quadratic Formula your pick

    • one year ago
  14. angelwings996
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    Okay, I'll use the Quadratic Formula so A = 1, B = 10 and C = 25 correct?

    • one year ago
  15. completeidiot
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    no, look at syhna's steps

    • one year ago
  16. angelwings996
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    Ohh sorry I was looking at the wrong one. A = 1 B = 8 and C = 35

    • one year ago
  17. completeidiot
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    yes

    • one year ago
  18. angelwings996
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    Okay, I get number 1 now, what about number 2 ?

    • one year ago
  19. completeidiot
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    i suggest factoring, for the practice

    • one year ago
  20. angelwings996
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    I'm not good at factoring at all, so that's why I am stuck

    • one year ago
  21. completeidiot
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    actually, yes use quadratic formula cause i dont think you can factor it

    • one year ago
  22. angelwings996
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    How would I figure out what A, B, and C is?

    • one year ago
  23. syhna
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    can #2 be subtracted ? i dont honestly get it

    • one year ago
  24. completeidiot
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    ax^2+bx+c=0

    • one year ago
  25. angelwings996
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    @completeidiot I'm not sure how to identify a, b, and c in the equation \[3\sqrt[3]{2a} - 6\sqrt[3]{2a}\]

    • one year ago
  26. completeidiot
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    oh for number 2 i said use distribution property of multiplication but in reverse

    • one year ago
  27. completeidiot
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    essentially the same as factoring

    • one year ago
  28. angelwings996
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    That's what I was asking lol. What do yu mean in reverse?

    • one year ago
  29. completeidiot
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    a(b+c)= ab+ac in reverse would be pulling something out de+df=d(e+f)

    • one year ago
  30. angelwings996
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    Couldn't I cancel out 2a or no

    • one year ago
  31. syhna
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    can this be \[\sqrt[3]{2a} = 2a ^{3}\] ?

    • one year ago
  32. angelwings996
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    It would actually be \[2a ^{1/3}\]

    • one year ago
  33. completeidiot
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    no it would be 1/3 not 3 and you're missing a parenthesis

    • one year ago
  34. syhna
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    a i see complete _ what you said a while ago about the reverse factoring then the prob should be equated to 0?

    • one year ago
  35. angelwings996
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    For the equation that you gave me @completeidiot de + df = d(e + f), would d be 2a ?

    • one year ago
  36. syhna
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    so cube of a times (3 -6) ????

    • one year ago
  37. angelwings996
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    @syhna How did you get that? Did you just substitute them into the equation completeidiot gave us?

    • one year ago
  38. completeidiot
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    yes syhna

    • one year ago
  39. syhna
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    the two terms had cuberoot of a

    • one year ago
  40. angelwings996
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    Oh so the answer for #2 is what you got?

    • one year ago
  41. completeidiot
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    2a

    • one year ago
  42. syhna
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    so it is -3(cube of 2a)? i think its just the same if we subtracted it

    • one year ago
  43. completeidiot
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    yes

    • one year ago
  44. angelwings996
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    Yeah, that's what I was thinking that if I had subtracted it I would of got what you came up with because at first I subtracted it and came up with that but wasn't sure if it was right

    • one year ago
  45. angelwings996
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    Okay, last question, what would I do for #3 ?

    • one year ago
  46. completeidiot
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    you're allowed to have improper fractions as exponents

    • one year ago
  47. angelwings996
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    Okay, I know you told me it was \[\sqrt[n]{x} = x ^{1/n}\] Is this an equation or the answer

    • one year ago
  48. angelwings996
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    @completeidiot

    • one year ago
  49. completeidiot
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    thats a general rule of thumbs

    • one year ago
  50. completeidiot
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    think of it as x^1

    • one year ago
  51. completeidiot
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    now replace the 1 with m

    • one year ago
  52. angelwings996
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    Okay so it would be \[x ^{m/n} ?\]

    • one year ago
  53. completeidiot
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    yup

    • one year ago
  54. angelwings996
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    Okay, could you go over my answer for number 1 really quick ?

    • one year ago
  55. angelwings996
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    The Quadratic formua is \[x = \frac{ -b \pm \sqrt{b ^{2} - 4ac} }{ 2a }\] right ?

    • one year ago
  56. completeidiot
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    yes

    • one year ago
  57. syhna
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    yeah i guess

    • one year ago
  58. angelwings996
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    Okay so I plugged it in nd got \[x = \frac{ -8 \pm \sqrt{-76} }{ 2 }\] after simplifying everything

    • one year ago
  59. syhna
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    in no 1 i dont think im right but i used completing the square and got \[-4\pm \sqrt{-19}\]

    • one year ago
  60. completeidiot
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    its an imaginary answer but its still an answer

    • one year ago
  61. completeidiot
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    either that or syhna messed up in his calcualtions

    • one year ago
  62. angelwings996
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    Wait, so mine was correct ? Or no

    • one year ago
  63. completeidiot
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    dunno, didnt actually do any of the problems

    • one year ago
  64. syhna
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    -35 =x^2 + 8x -35 + 16 = x^2 + 8x + 16 -19 = sqrt(x+4) sqrt(-19) = x + 4 \[-4\pm \sqrt{-19}\] = x this is what i did.. dunno where i messed up

    • one year ago
  65. angelwings996
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    I'm not sure either, but thanks for trying to do the work with me! You were alot of help

    • one year ago
  66. syhna
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    welcome

    • one year ago
  67. whpalmer4
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    \[x=-4\pm\sqrt{-19} = -4\pm i \sqrt{19} \] is correct

    • one year ago
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