## angelwings996 Group Title Couple of Math questions, please help! 1. What is the solution of the equation? sqrt(2x - 10) - 5 = x 2. What is the simplest form of the radical expression? 3*cube root(2a) - 6*cube root(2a) 3. Rewrite ^n sqrt(x^m) using a rational expression one year ago one year ago

1. angelwings996 Group Title

For Number 2$3\sqrt[3]{2a} - 6\sqrt[3]{2a}$

2. angelwings996 Group Title

For number 3 $\sqrt[n]{x ^{m}}$

3. completeidiot Group Title

number 1- move the 5 over to the other side square both sides expand solve for zero on one side factor solve for x

4. completeidiot Group Title

number 2- use the distribution property of multiplication but backwards

5. sammi904 Group Title

Part 1: Solve the following quadratic equation using one of the methods listed below. Part 2: Using complete sentences, explain why you chose the method you used. Equation: 0 = x2 + 6x + 3 Methods: Completing the Square Factoring Quadratic Formula Graphing can someone help?

6. angelwings996 Group Title

@sammi904 Why do I need to explain the methods I used ?

7. completeidiot Group Title

number 3 $\sqrt[n]{x}=x^{\frac{1}{n}}$

8. angelwings996 Group Title

@completeidiot so far for number 1, I got $2x + 13 = 5x ^{2}$

9. completeidiot Group Title

you screwed up somewhere please show me steps

10. angelwings996 Group Title

Oh I think I get what I did wrong. I times 5 with x instead of adding it so it would be $2x + 10 = (x + 5)^{2}$ Right?

11. syhna Group Title

2x-10 = (x+5)^2 2x-10 = x^2 + 10x + 25 0 = x^2 + 8x + 35

12. angelwings996 Group Title

Okay, but how would you find the solution of the equation? @syhna

13. completeidiot Group Title

14. angelwings996 Group Title

Okay, I'll use the Quadratic Formula so A = 1, B = 10 and C = 25 correct?

15. completeidiot Group Title

no, look at syhna's steps

16. angelwings996 Group Title

Ohh sorry I was looking at the wrong one. A = 1 B = 8 and C = 35

17. completeidiot Group Title

yes

18. angelwings996 Group Title

Okay, I get number 1 now, what about number 2 ?

19. completeidiot Group Title

i suggest factoring, for the practice

20. angelwings996 Group Title

I'm not good at factoring at all, so that's why I am stuck

21. completeidiot Group Title

actually, yes use quadratic formula cause i dont think you can factor it

22. angelwings996 Group Title

How would I figure out what A, B, and C is?

23. syhna Group Title

can #2 be subtracted ? i dont honestly get it

24. completeidiot Group Title

ax^2+bx+c=0

25. angelwings996 Group Title

@completeidiot I'm not sure how to identify a, b, and c in the equation $3\sqrt[3]{2a} - 6\sqrt[3]{2a}$

26. completeidiot Group Title

oh for number 2 i said use distribution property of multiplication but in reverse

27. completeidiot Group Title

essentially the same as factoring

28. angelwings996 Group Title

That's what I was asking lol. What do yu mean in reverse?

29. completeidiot Group Title

a(b+c)= ab+ac in reverse would be pulling something out de+df=d(e+f)

30. angelwings996 Group Title

Couldn't I cancel out 2a or no

31. syhna Group Title

can this be $\sqrt[3]{2a} = 2a ^{3}$ ?

32. angelwings996 Group Title

It would actually be $2a ^{1/3}$

33. completeidiot Group Title

no it would be 1/3 not 3 and you're missing a parenthesis

34. syhna Group Title

a i see complete _ what you said a while ago about the reverse factoring then the prob should be equated to 0?

35. angelwings996 Group Title

For the equation that you gave me @completeidiot de + df = d(e + f), would d be 2a ?

36. syhna Group Title

so cube of a times (3 -6) ????

37. angelwings996 Group Title

@syhna How did you get that? Did you just substitute them into the equation completeidiot gave us?

38. completeidiot Group Title

yes syhna

39. syhna Group Title

the two terms had cuberoot of a

40. angelwings996 Group Title

Oh so the answer for #2 is what you got?

41. completeidiot Group Title

2a

42. syhna Group Title

so it is -3(cube of 2a)? i think its just the same if we subtracted it

43. completeidiot Group Title

yes

44. angelwings996 Group Title

Yeah, that's what I was thinking that if I had subtracted it I would of got what you came up with because at first I subtracted it and came up with that but wasn't sure if it was right

45. angelwings996 Group Title

Okay, last question, what would I do for #3 ?

46. completeidiot Group Title

you're allowed to have improper fractions as exponents

47. angelwings996 Group Title

Okay, I know you told me it was $\sqrt[n]{x} = x ^{1/n}$ Is this an equation or the answer

48. angelwings996 Group Title

@completeidiot

49. completeidiot Group Title

thats a general rule of thumbs

50. completeidiot Group Title

think of it as x^1

51. completeidiot Group Title

now replace the 1 with m

52. angelwings996 Group Title

Okay so it would be $x ^{m/n} ?$

53. completeidiot Group Title

yup

54. angelwings996 Group Title

Okay, could you go over my answer for number 1 really quick ?

55. angelwings996 Group Title

The Quadratic formua is $x = \frac{ -b \pm \sqrt{b ^{2} - 4ac} }{ 2a }$ right ?

56. completeidiot Group Title

yes

57. syhna Group Title

yeah i guess

58. angelwings996 Group Title

Okay so I plugged it in nd got $x = \frac{ -8 \pm \sqrt{-76} }{ 2 }$ after simplifying everything

59. syhna Group Title

in no 1 i dont think im right but i used completing the square and got $-4\pm \sqrt{-19}$

60. completeidiot Group Title

61. completeidiot Group Title

either that or syhna messed up in his calcualtions

62. angelwings996 Group Title

Wait, so mine was correct ? Or no

63. completeidiot Group Title

dunno, didnt actually do any of the problems

64. syhna Group Title

-35 =x^2 + 8x -35 + 16 = x^2 + 8x + 16 -19 = sqrt(x+4) sqrt(-19) = x + 4 $-4\pm \sqrt{-19}$ = x this is what i did.. dunno where i messed up

65. angelwings996 Group Title

I'm not sure either, but thanks for trying to do the work with me! You were alot of help

66. syhna Group Title

welcome

67. whpalmer4 Group Title

$x=-4\pm\sqrt{-19} = -4\pm i \sqrt{19}$ is correct