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whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2Put both equations in slopeintercept form: y = mx + b where m is slope and b is yintercept. If they are parallel, slopes will be =. If they are perpendicular, the product of the two slopes will be 1. Otherwise, they are none of the above.

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2Slope of first line is 2/3. Second equation we need to solve for y: [\2x3y=3\]\[2x+3=3y\]\[y=\frac{2}{3}x+1\] so slope of second line is 2/3. \[\frac{2}{3}*\frac{2}{3} = \frac{4}{9} \] so they are not perpendicular.

sammietaygreen
 one year ago
Best ResponseYou've already chosen the best response.0Yes, yes. I know it can't be perpendicular.

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2Well, that also shows that they are not parallel because the slopes are not equal.

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2Need to check your work if you graphed them and got parallel lines :)

sammietaygreen
 one year ago
Best ResponseYou've already chosen the best response.0Ohhh, I must have graphed wrong. That simplified it a bit, @jim_thompson5910 is helping me as well. I'm going to check what I did wrong

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2I always use x = 0 as one of my graph points :)

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2In this case, it doesn't help because they actually cross at x =0, but often that isn't the case, and the arithmetic is a bit easier!

sammietaygreen
 one year ago
Best ResponseYou've already chosen the best response.0could you help on one more on this thread?
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