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sammietaygreen
attachment!
Put both equations in slope-intercept form: y = mx + b where m is slope and b is y-intercept. If they are parallel, slopes will be =. If they are perpendicular, the product of the two slopes will be -1. Otherwise, they are none of the above.
Slope of first line is -2/3. Second equation we need to solve for y: [\2x-3y=-3\]\[2x+3=3y\]\[y=\frac{2}{3}x+1\] so slope of second line is 2/3. \[\frac{2}{3}*-\frac{2}{3} = -\frac{4}{9} \] so they are not perpendicular.
Yes, yes. I know it can't be perpendicular.
Well, that also shows that they are not parallel because the slopes are not equal.
Need to check your work if you graphed them and got parallel lines :-)
Ohhh, I must have graphed wrong. That simplified it a bit, @jim_thompson5910 is helping me as well. I'm going to check what I did wrong
I always use x = 0 as one of my graph points :-)
In this case, it doesn't help because they actually cross at x =0, but often that isn't the case, and the arithmetic is a bit easier!
could you help on one more on this thread?