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whpalmer4Best ResponseYou've already chosen the best response.2
Put both equations in slopeintercept form: y = mx + b where m is slope and b is yintercept. If they are parallel, slopes will be =. If they are perpendicular, the product of the two slopes will be 1. Otherwise, they are none of the above.
 one year ago

whpalmer4Best ResponseYou've already chosen the best response.2
Slope of first line is 2/3. Second equation we need to solve for y: [\2x3y=3\]\[2x+3=3y\]\[y=\frac{2}{3}x+1\] so slope of second line is 2/3. \[\frac{2}{3}*\frac{2}{3} = \frac{4}{9} \] so they are not perpendicular.
 one year ago

sammietaygreenBest ResponseYou've already chosen the best response.0
Yes, yes. I know it can't be perpendicular.
 one year ago

whpalmer4Best ResponseYou've already chosen the best response.2
Well, that also shows that they are not parallel because the slopes are not equal.
 one year ago

whpalmer4Best ResponseYou've already chosen the best response.2
Need to check your work if you graphed them and got parallel lines :)
 one year ago

sammietaygreenBest ResponseYou've already chosen the best response.0
Ohhh, I must have graphed wrong. That simplified it a bit, @jim_thompson5910 is helping me as well. I'm going to check what I did wrong
 one year ago

whpalmer4Best ResponseYou've already chosen the best response.2
I always use x = 0 as one of my graph points :)
 one year ago

whpalmer4Best ResponseYou've already chosen the best response.2
In this case, it doesn't help because they actually cross at x =0, but often that isn't the case, and the arithmetic is a bit easier!
 one year ago

sammietaygreenBest ResponseYou've already chosen the best response.0
could you help on one more on this thread?
 one year ago
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