sammietaygreen
  • sammietaygreen
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Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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whpalmer4
  • whpalmer4
Put both equations in slope-intercept form: y = mx + b where m is slope and b is y-intercept. If they are parallel, slopes will be =. If they are perpendicular, the product of the two slopes will be -1. Otherwise, they are none of the above.
whpalmer4
  • whpalmer4
Slope of first line is -2/3. Second equation we need to solve for y: [\2x-3y=-3\]\[2x+3=3y\]\[y=\frac{2}{3}x+1\] so slope of second line is 2/3. \[\frac{2}{3}*-\frac{2}{3} = -\frac{4}{9} \] so they are not perpendicular.
sammietaygreen
  • sammietaygreen
Yes, yes. I know it can't be perpendicular.

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whpalmer4
  • whpalmer4
Well, that also shows that they are not parallel because the slopes are not equal.
whpalmer4
  • whpalmer4
Need to check your work if you graphed them and got parallel lines :-)
sammietaygreen
  • sammietaygreen
Ohhh, I must have graphed wrong. That simplified it a bit, @jim_thompson5910 is helping me as well. I'm going to check what I did wrong
whpalmer4
  • whpalmer4
I always use x = 0 as one of my graph points :-)
sammietaygreen
  • sammietaygreen
thanks! :)
whpalmer4
  • whpalmer4
In this case, it doesn't help because they actually cross at x =0, but often that isn't the case, and the arithmetic is a bit easier!
sammietaygreen
  • sammietaygreen
could you help on one more on this thread?

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