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sammietaygreen
 3 years ago
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sammietaygreen
 3 years ago
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whpalmer4
 3 years ago
Best ResponseYou've already chosen the best response.2Put both equations in slopeintercept form: y = mx + b where m is slope and b is yintercept. If they are parallel, slopes will be =. If they are perpendicular, the product of the two slopes will be 1. Otherwise, they are none of the above.

whpalmer4
 3 years ago
Best ResponseYou've already chosen the best response.2Slope of first line is 2/3. Second equation we need to solve for y: [\2x3y=3\]\[2x+3=3y\]\[y=\frac{2}{3}x+1\] so slope of second line is 2/3. \[\frac{2}{3}*\frac{2}{3} = \frac{4}{9} \] so they are not perpendicular.

sammietaygreen
 3 years ago
Best ResponseYou've already chosen the best response.0Yes, yes. I know it can't be perpendicular.

whpalmer4
 3 years ago
Best ResponseYou've already chosen the best response.2Well, that also shows that they are not parallel because the slopes are not equal.

whpalmer4
 3 years ago
Best ResponseYou've already chosen the best response.2Need to check your work if you graphed them and got parallel lines :)

sammietaygreen
 3 years ago
Best ResponseYou've already chosen the best response.0Ohhh, I must have graphed wrong. That simplified it a bit, @jim_thompson5910 is helping me as well. I'm going to check what I did wrong

whpalmer4
 3 years ago
Best ResponseYou've already chosen the best response.2I always use x = 0 as one of my graph points :)

whpalmer4
 3 years ago
Best ResponseYou've already chosen the best response.2In this case, it doesn't help because they actually cross at x =0, but often that isn't the case, and the arithmetic is a bit easier!

sammietaygreen
 3 years ago
Best ResponseYou've already chosen the best response.0could you help on one more on this thread?
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