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Find all values of k so that each polynomial can be factored using integers.
1.) x^2+kx19
2.) x^2  8x+k, k>0
 one year ago
 one year ago
Find all values of k so that each polynomial can be factored using integers. 1.) x^2+kx19 2.) x^2  8x+k, k>0
 one year ago
 one year ago

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klimenkovBest ResponseYou've already chosen the best response.1
what means using integers?
 one year ago

klimenkovBest ResponseYou've already chosen the best response.1
Integer roots or integer value of k?
 one year ago

MissKelly~Best ResponseYou've already chosen the best response.0
I don't know...I just wrote word for word for what it says in the book...All I know is that for #1 the answers will be in integers...
 one year ago

klimenkovBest ResponseYou've already chosen the best response.1
For the first one: 18, 18.
 one year ago

MissKelly~Best ResponseYou've already chosen the best response.0
How do you solve it? Distributive...factor?
 one year ago

klimenkovBest ResponseYou've already chosen the best response.1
Do you know Vieta's Theorem?
 one year ago

MissKelly~Best ResponseYou've already chosen the best response.0
Not yet, The questions I got was from the book on the chapter of Quadratic equations, and it said it required Higherorder thinking skills...
 one year ago

MissKelly~Best ResponseYou've already chosen the best response.0
So you factor it out into 2 binomials?
 one year ago

klimenkovBest ResponseYou've already chosen the best response.1
Vieta's Theorem is not so hard to get. I advice you to get it and try to use for your task.
 one year ago

MissKelly~Best ResponseYou've already chosen the best response.0
I'm not so sure my teacher wants me to apply Vieta's Theorem yet, because she hates it when we move on ahead of her teachings...btw she can't teach =_=
 one year ago

MissKelly~Best ResponseYou've already chosen the best response.0
Well I have to leave for school in a little while, there's a chemical equation quiz waiting for me...
 one year ago

MissKelly~Best ResponseYou've already chosen the best response.0
Thanks for helping me~
 one year ago

MissKelly~Best ResponseYou've already chosen the best response.0
Hehe why is that? Well I'm sorry I have to go to school now..
 one year ago

MissKelly~Best ResponseYou've already chosen the best response.0
See you guys around^^ Bye
 one year ago

klimenkovBest ResponseYou've already chosen the best response.1
If you want to factor \(x^2+kx19\), I hope you will think it will be \((xa)(xb)\). So, when expanding: \(x^2(a+b)x+ab\). Now just look at the coefficients. \(k=(a+b), 19=ab\). You want only integers. From the second equality it will be only \(a=1,b=19\) or \(a=19,b=1\), because 19 is a prime number. Now try to find \(k\) in both cases.
 one year ago

klimenkovBest ResponseYou've already chosen the best response.1
Just try to explain. Not so sure he got it.
 one year ago

klimenkovBest ResponseYou've already chosen the best response.1
If \((a+b)=8\), so \(a+b=8\). And \(ab=k\), we get \(a(8a)=k>0\). It will be if \(a^2+8a>0\).dw:1357824979524:dw Answer: 1, 2, 3, 4, 5, 6, 7.
 one year ago

klimenkovBest ResponseYou've already chosen the best response.1
Oops. Sorry, it's not right.
 one year ago

klimenkovBest ResponseYou've already chosen the best response.1
The answer will be if you put all this numbers: 1, 2, 3, 4, 5, 6, 7 in the expression for \(k=a(8a)\) instead of \(a\).
 one year ago

klimenkovBest ResponseYou've already chosen the best response.1
How did you get that this will be all the possible values for \(k\), that you've written k = {0, 7, 12, 15, 16}? \(k=0\) doesn't suit.
 one year ago

klimenkovBest ResponseYou've already chosen the best response.1
\(k>0\) in the statement.
 one year ago

klimenkovBest ResponseYou've already chosen the best response.1
I can't be absolutely sure that this will be ALL the values for \(k\) by just guessing its value.
 one year ago

klimenkovBest ResponseYou've already chosen the best response.1
The source of our misunderstanding is my bad English. Sometimes I can't get what is spoken about.
 one year ago

klimenkovBest ResponseYou've already chosen the best response.1
You say that it is no need in writing \(k=a(8a), a=1,2,\ldots ,7\). Because it will have the same value for \(a=1\) and \(a=7\). I just showed the way I had solved this task. Sorry.
 one year ago

MissKelly~Best ResponseYou've already chosen the best response.0
Okay I'm back...whoooooa. And yeah I got it now^^
 one year ago
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