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 2 years ago
Find all values of k so that each polynomial can be factored using integers.
1.) x^2+kx19
2.) x^2  8x+k, k>0
 2 years ago
Find all values of k so that each polynomial can be factored using integers. 1.) x^2+kx19 2.) x^2  8x+k, k>0

This Question is Closed

klimenkov
 2 years ago
Best ResponseYou've already chosen the best response.1what means using integers?

klimenkov
 2 years ago
Best ResponseYou've already chosen the best response.1Integer roots or integer value of k?

MissKelly~
 2 years ago
Best ResponseYou've already chosen the best response.0I don't know...I just wrote word for word for what it says in the book...All I know is that for #1 the answers will be in integers...

klimenkov
 2 years ago
Best ResponseYou've already chosen the best response.1For the first one: 18, 18.

MissKelly~
 2 years ago
Best ResponseYou've already chosen the best response.0How do you solve it? Distributive...factor?

klimenkov
 2 years ago
Best ResponseYou've already chosen the best response.1Do you know Vieta's Theorem?

MissKelly~
 2 years ago
Best ResponseYou've already chosen the best response.0Not yet, The questions I got was from the book on the chapter of Quadratic equations, and it said it required Higherorder thinking skills...

MissKelly~
 2 years ago
Best ResponseYou've already chosen the best response.0So you factor it out into 2 binomials?

klimenkov
 2 years ago
Best ResponseYou've already chosen the best response.1Vieta's Theorem is not so hard to get. I advice you to get it and try to use for your task.

MissKelly~
 2 years ago
Best ResponseYou've already chosen the best response.0I'm not so sure my teacher wants me to apply Vieta's Theorem yet, because she hates it when we move on ahead of her teachings...btw she can't teach =_=

MissKelly~
 2 years ago
Best ResponseYou've already chosen the best response.0Well I have to leave for school in a little while, there's a chemical equation quiz waiting for me...

MissKelly~
 2 years ago
Best ResponseYou've already chosen the best response.0Thanks for helping me~

MissKelly~
 2 years ago
Best ResponseYou've already chosen the best response.0Hehe why is that? Well I'm sorry I have to go to school now..

MissKelly~
 2 years ago
Best ResponseYou've already chosen the best response.0See you guys around^^ Bye

klimenkov
 2 years ago
Best ResponseYou've already chosen the best response.1If you want to factor \(x^2+kx19\), I hope you will think it will be \((xa)(xb)\). So, when expanding: \(x^2(a+b)x+ab\). Now just look at the coefficients. \(k=(a+b), 19=ab\). You want only integers. From the second equality it will be only \(a=1,b=19\) or \(a=19,b=1\), because 19 is a prime number. Now try to find \(k\) in both cases.

klimenkov
 2 years ago
Best ResponseYou've already chosen the best response.1Just try to explain. Not so sure he got it.

klimenkov
 2 years ago
Best ResponseYou've already chosen the best response.1If \((a+b)=8\), so \(a+b=8\). And \(ab=k\), we get \(a(8a)=k>0\). It will be if \(a^2+8a>0\).dw:1357824979524:dw Answer: 1, 2, 3, 4, 5, 6, 7.

klimenkov
 2 years ago
Best ResponseYou've already chosen the best response.1Oops. Sorry, it's not right.

klimenkov
 2 years ago
Best ResponseYou've already chosen the best response.1The answer will be if you put all this numbers: 1, 2, 3, 4, 5, 6, 7 in the expression for \(k=a(8a)\) instead of \(a\).

klimenkov
 2 years ago
Best ResponseYou've already chosen the best response.1How did you get that this will be all the possible values for \(k\), that you've written k = {0, 7, 12, 15, 16}? \(k=0\) doesn't suit.

klimenkov
 2 years ago
Best ResponseYou've already chosen the best response.1\(k>0\) in the statement.

klimenkov
 2 years ago
Best ResponseYou've already chosen the best response.1I can't be absolutely sure that this will be ALL the values for \(k\) by just guessing its value.

klimenkov
 2 years ago
Best ResponseYou've already chosen the best response.1The source of our misunderstanding is my bad English. Sometimes I can't get what is spoken about.

klimenkov
 2 years ago
Best ResponseYou've already chosen the best response.1You say that it is no need in writing \(k=a(8a), a=1,2,\ldots ,7\). Because it will have the same value for \(a=1\) and \(a=7\). I just showed the way I had solved this task. Sorry.

MissKelly~
 2 years ago
Best ResponseYou've already chosen the best response.0Okay I'm back...whoooooa. And yeah I got it now^^
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