sapphers
(sqrt2x+13)  15 = x



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Mertsj
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Add 15 to both sides and then square both sides.

sapphers
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I'm still kind of confused

Mertsj
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Did you add 15 to both sides?

sapphers
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Yeah, I did.

Mertsj
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What did you get?

sapphers
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\[\sqrt{2x+13} = x + 15\]

Mertsj
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What do you get if you square the left side?

Mertsj
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\[(\sqrt{2x=13})^2= ?\]

Mertsj
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Sorry. I meant + 13 not =

TheViper
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\[\large{\sqrt{2x+13}15=x}\]\[\large{\sqrt{2x+13}=x+15}\]Now squaring both sides we get\[\large{2x+13=x^2+225+30x}\]

Mertsj
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You must not square each side. So now it will look like this:
\[(\sqrt{2x+13})^2=(x+15)^2\]

Mertsj
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ok. Too many cooks. Good bye

TheViper
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bye :)

sapphers
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Thanks for leaving I guess... @Mertsj
@TheViper are you leaving too or saying goodbye to the other guy?

TheViper
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no

sapphers
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Okay haha

TheViper
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\[\large{2x+13=x^2+225+30x}\]\[\large{\implies x^2+30x2x+22513=0}\]\[\large{\implies x^2+28x+212=0}\]Now solve it by factoring :)

sapphers
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You two were both telling me different things. How do I know that yours it right?

TheViper
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We are telling same but concentrate on mine because I m here to help you :)

Mertsj
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It won't factor. You'll have to use the quadratic formula.

sapphers
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I tried factoring and it didn't work. So I plug x^2 + 28x + 212 into the quadratic formula?

Mertsj
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yes

TheViper
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yup :)

TheViper
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I think it should be \(14+2i\) \(\&\) \(142i\)

TheViper
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Check ur calculation again :)