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sapphers Group Title

(sqrt2x+13) - 15 = x

  • one year ago
  • one year ago

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  1. Mertsj Group Title
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    Add 15 to both sides and then square both sides.

    • one year ago
  2. sapphers Group Title
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    I'm still kind of confused

    • one year ago
  3. Mertsj Group Title
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    Did you add 15 to both sides?

    • one year ago
  4. sapphers Group Title
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    Yeah, I did.

    • one year ago
  5. Mertsj Group Title
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    What did you get?

    • one year ago
  6. sapphers Group Title
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    \[\sqrt{2x+13} = x + 15\]

    • one year ago
  7. Mertsj Group Title
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    What do you get if you square the left side?

    • one year ago
  8. Mertsj Group Title
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    \[(\sqrt{2x=13})^2= ?\]

    • one year ago
  9. Mertsj Group Title
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    Sorry. I meant + 13 not =

    • one year ago
  10. TheViper Group Title
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    \[\large{\sqrt{2x+13}-15=x}\]\[\large{\sqrt{2x+13}=x+15}\]Now squaring both sides we get\[\large{2x+13=x^2+225+30x}\]

    • one year ago
  11. Mertsj Group Title
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    You must not square each side. So now it will look like this: \[(\sqrt{2x+13})^2=(x+15)^2\]

    • one year ago
  12. Mertsj Group Title
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    ok. Too many cooks. Good bye

    • one year ago
  13. TheViper Group Title
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    bye :)

    • one year ago
  14. sapphers Group Title
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    Thanks for leaving I guess... @Mertsj @TheViper are you leaving too or saying goodbye to the other guy?

    • one year ago
  15. TheViper Group Title
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    no

    • one year ago
  16. sapphers Group Title
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    Okay haha

    • one year ago
  17. TheViper Group Title
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    \[\large{2x+13=x^2+225+30x}\]\[\large{\implies x^2+30x-2x+225-13=0}\]\[\large{\implies x^2+28x+212=0}\]Now solve it by factoring :)

    • one year ago
  18. sapphers Group Title
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    You two were both telling me different things. How do I know that yours it right?

    • one year ago
  19. TheViper Group Title
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    We are telling same but concentrate on mine because I m here to help you :)

    • one year ago
  20. Mertsj Group Title
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    It won't factor. You'll have to use the quadratic formula.

    • one year ago
  21. sapphers Group Title
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    I tried factoring and it didn't work. So I plug x^2 + 28x + 212 into the quadratic formula?

    • one year ago
  22. Mertsj Group Title
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    yes

    • one year ago
  23. TheViper Group Title
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    yup :)

    • one year ago
  24. TheViper Group Title
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    I think it should be \(-14+2i\) \(\&\) \(-14-2i\)

    • one year ago
  25. TheViper Group Title
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    Check ur calculation again :)

    • one year ago
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