A community for students.
Here's the question you clicked on:
 0 viewing
kymber
 2 years ago
An object is launched at 19.6 m/s from a height of 58.8 m. The equation for the height (h) in terms of time (t) is given by h(t) = 4.9t² +19.6t + 58.8. What is the object's maximum height?
kymber
 2 years ago
An object is launched at 19.6 m/s from a height of 58.8 m. The equation for the height (h) in terms of time (t) is given by h(t) = 4.9t² +19.6t + 58.8. What is the object's maximum height?

This Question is Closed

SmoothMath
 2 years ago
Best ResponseYou've already chosen the best response.1There are a couple of ways to solve this, and the method you should use depends on the type of math course you are in. Is this for a calculus course or an algebra course?

kymber
 2 years ago
Best ResponseYou've already chosen the best response.2It's algebra two, year three in high school.

SmoothMath
 2 years ago
Best ResponseYou've already chosen the best response.1Ah, okay. Then the way to solve this is to recognize that the equation for the height is going to give you a parabola opening downward. The highest point will be at the vertex of that parabola. Do you know how to find the vertex?

SmoothMath
 2 years ago
Best ResponseYou've already chosen the best response.1The x coordinate of the vertex will always be \(\Large \frac{b}{2a}\). In this case, that will give you the time that the ball is at its highest point. From there, if you want to figure out the height, you can just plug that time into h(t).

SmoothMath
 2 years ago
Best ResponseYou've already chosen the best response.1Let me know if you have any questions.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.