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you're right ... I think

I think you are allowed to use duplicates.

Now, did you attempt the second part?

What? Please englighten me. Ywah I confused of the next part too.

Nahs. I don't think there is minus included. Because they'll list - number too if that wa the case

D<0 imaginary

I don't see any way to get 88. If it turns out to be 88, I would like to know how.

Good, so out of the elements of the set, which element(s) put in "b" will give real zeroes?

or which are the combinations that will give real zeroes?

There is so many combination I can't even begin to think

There is a maximum of 48, but many of them are obvious.

there are 48 combinations. brute force will work

There is at least 12 tho. Put c=0. so 4*3*1

i got 21 what did you get?

Do you mind showing your work?

Really? I believe found more than 18 quadratic equations with imaginary roots.

Yes, I have 30 for complex, and 18 for real.