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ErinWeeks

  • one year ago

Find mBAC in circle O. (The figure is not drawn to scale.)

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  1. ErinWeeks
    • one year ago
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  2. ErinWeeks
    • one year ago
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    A. 170 B. 95 C. 47.5 D. 42.5

  3. arandomguy
    • one year ago
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    do u go to connexus

  4. ErinWeeks
    • one year ago
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    no i go to James Madison

  5. arandomguy
    • one year ago
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    i was on the unit 6 test and was wondering if someone could help me with some problems

  6. ErinWeeks
    • one year ago
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    im on exam 6 test to

  7. SmoothMath
    • one year ago
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    Oh, hey. Real simple. If you can figure out the measure of the arc that the inscribed angle subtends, then the angle will simply be: \[\Large \text{inscribed angle} = \frac{\text{measure of arc subtended}}{2}\]

  8. ErinWeeks
    • one year ago
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    i dont know how to figure that out the arc -_-

  9. SmoothMath
    • one year ago
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    |dw:1357873734885:dw|

  10. ErinWeeks
    • one year ago
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    so it would be 85 .. then what do you do? can you show me

  11. SmoothMath
    • one year ago
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    naw gurl. it aint even.

  12. ErinWeeks
    • one year ago
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    im confused ...

  13. SmoothMath
    • one year ago
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    I can tell.

  14. ErinWeeks
    • one year ago
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    Helppp lol

  15. ErinWeeks
    • one year ago
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    would it be 90? 95? I dont know lol

  16. SmoothMath
    • one year ago
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    I'm sorry. The whole guessing business just kills me. Stop guessing, stop begging for answers, and show some effort.

  17. ErinWeeks
    • one year ago
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    i am i dont know how to do this, Im trying ..

  18. SmoothMath
    • one year ago
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    All of the facts you need: Two angles that form a straight line must add up to 180 degrees. An arc has the same measure as a central angle that includes it. An inscribed angle is half of the measure of the arc it includes.

  19. mathmate
    • one year ago
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    |dw:1357910861134:dw| @ErinWeeks We should never guess in math, or else you will always have 25% or thereabouts for your grades! :( The above diagram shows the relation between the angles subtended by the same chord AC, at the circumference B or at the centre O. If you join OB, then OA,OB,OC are all equal to the radius. Thus triangl OAB is isosceles, therefore mBAO=mABO. Similarly mBCO=mCBO. But mABO+mCBO=mAOC (exterior angles), which means finally \( mAOC=2 * mABC.\) Hope this helps. Note: this is similar to the question I answered previously. Hope that this more detailed explanation helps you work on other problems. Please, do NOT guess your answers if you want a good grade. Understanding is faster than guessing.

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