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Find mBAC in circle O. (The figure is not drawn to scale.)

Mathematics
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1 Attachment
A. 170 B. 95 C. 47.5 D. 42.5
do u go to connexus

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Other answers:

no i go to James Madison
i was on the unit 6 test and was wondering if someone could help me with some problems
im on exam 6 test to
Oh, hey. Real simple. If you can figure out the measure of the arc that the inscribed angle subtends, then the angle will simply be: \[\Large \text{inscribed angle} = \frac{\text{measure of arc subtended}}{2}\]
i dont know how to figure that out the arc -_-
|dw:1357873734885:dw|
so it would be 85 .. then what do you do? can you show me
naw gurl. it aint even.
im confused ...
I can tell.
Helppp lol
would it be 90? 95? I dont know lol
I'm sorry. The whole guessing business just kills me. Stop guessing, stop begging for answers, and show some effort.
i am i dont know how to do this, Im trying ..
All of the facts you need: Two angles that form a straight line must add up to 180 degrees. An arc has the same measure as a central angle that includes it. An inscribed angle is half of the measure of the arc it includes.
|dw:1357910861134:dw| @ErinWeeks We should never guess in math, or else you will always have 25% or thereabouts for your grades! :( The above diagram shows the relation between the angles subtended by the same chord AC, at the circumference B or at the centre O. If you join OB, then OA,OB,OC are all equal to the radius. Thus triangl OAB is isosceles, therefore mBAO=mABO. Similarly mBCO=mCBO. But mABO+mCBO=mAOC (exterior angles), which means finally \( mAOC=2 * mABC.\) Hope this helps. Note: this is similar to the question I answered previously. Hope that this more detailed explanation helps you work on other problems. Please, do NOT guess your answers if you want a good grade. Understanding is faster than guessing.

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